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OLga [1]
3 years ago
8

Linear equations 3y+2=5

Mathematics
2 answers:
Ivan3 years ago
6 0

Hey!

I'm assuming that you would like to solve this equation for y:

3y + 2 = 5

3y = 3

y = 1

As an explanation of what I did, I first subtracted 2 from both sides so that I could isolate the y. Since the y had a coefficient of 3 I had to divide both side by 3, which gave us that y = 1.

tatuchka [14]3 years ago
3 0
Brainliest
3y+2=5
3y=5-2
3y=3
y=1
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Read 2 more answers
What is the equation of the line that passes through the points (-3,0.5) and (3,-0.5)
MakcuM [25]

Answer:

y = -1/6x + 0

Step-by-step explanation:

Using the equation of line

y_2 - y_1 / x_2 - x_1 = y - y_1 / x_1

Using the information we are provided with

( -3, 0.5)(3 , -0.5)

y_1 = 0.5

x_1 = -3

x_2 = 3

y_2 = -0.5

-0.5 - 0.5 / 3- (-3) = y - 0.5 / x - (-3)

-0.5 - 0.5 / 3 +3 = y - 0.5 / x + 3

-1 / 6 = y - 0.5 / x + 3

Cross multiply

-1(x + 3) = 6(y - 0.5)

Open the brackets

-x - 3 = 6y - 3

-x - 3 + 3 = 6y

-x + 0 = 6y

Divide through by 6 to get y

Following the eqn y = mx + C

-x + 0 / 6 = 6y / 6

y = -x + 0 / 6

We can separate it

y = -x / 6 + 0/6

y = -1/6x + 0

Therefore, the equation of the line is

y = -1/6x + 0

7 0
3 years ago
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