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3 years ago

Need work shown for this please. 7√144 - 11√45 + 6√500

Mathematics

2 answers:

pochemuha3 years ago

6 0

Answer:

Step-by-step explanation:

7√144 - 11√45 + 6√500

= 7(12) - 11√(9×5) + 6√(100×5)

= 84 - 11(3)√5 + 6(10)√5

= 84 - 33√5 + 60√5

= 84 + 27√5

Ivanshal [37]3 years ago

3 0

Answer:

7√144 - 11√45 + 6√500 = 84 + 27√5

Step-by-step explanation:

7√144 - 11√45 + 6√500

= 7(12) - 11(√9×√5) + 6(√100×√5)

= 84 - 33 √5 + 6(10×√5)

= 84 - 33 √5 + 60√5

= 84 + 27√5

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Plz help me with this...there might be errors in this but I'm not sure

Flura [38]

Step-by-step explanation:

1. cot(A − B)

From angle sum/difference equations, we know this equals:

cot(A − B) = (cot A cot B + 1) / (cot B − cot A)

But we also know it equals:

cot(A − B) = 1 / tan(A − B)

cot(A − B) = (1 + tan A tan B) / (tan A − tan B)

Setting the two equal to each other:

(cot A cot B + 1) / (cot B − cot A) = (1 + tan A tan B) / (tan A − tan B)

Writing tangent in terms of cotangent:

(cot A cot B + 1) / (cot B − cot A) = (1 + 1 / (cot A cot B)) / (tan A − tan B)

(cot A cot B + 1) / (cot B − cot A) = ((cot A cot B + 1) / (cot A cot B)) / (tan A − tan B)

(cot A cot B + 1) / (cot B − cot A) = (cot A cot B + 1) / ((cot A cot B) (tan A − tan B))

Divide both sides by the numerator:

1 / (cot B − cot A) = 1 / ((cot A cot B) (tan A − tan B))

Take inverse of both sides:

cot B − cot A = (cot A cot B) (tan A − tan B)

Solve for cot A cot B:

cot A cot B = (cot B − cot A) / (tan A − tan B)

cot A cot B = a / b

Now substitute into the first angle difference equation we wrote earlier:

cot(A − B) = (cot A cot B + 1) / (cot B − cot A)

cot(A − B) = (a / b + 1) / a

cot(A − B) = (a / b) / a + 1 / a

cot(A − B) = 1 / b + 1 / a

2. cos A / (1 ± sin A)

From angle sum/difference formulas, we know:

sin (90 ± A) = cos A

cos (90 ± A) = ∓ sin A

Substituting:

sin (90 ± A) / (1 − cos (90 ± A))

From half angle formula, this equals:

cot (45 ± A/2)

Using reflection:

-cot (-45 ∓ A/2)

And finally, phase shift:

tan (-45 ∓ A/2 + 90)

tan (45 ∓ A/2)

Check that you wrote the problem correctly. Looks like you switched ∓ with ±.

8 0

3 years ago

Which construction is being shown in the diagram?

11Alexandr11 [23.1K]

Answer:

Correct answer is option D) Construct the bisector of an angle.

Step-by-step explanation:

Angle bisector of an angle is a line that divides the angle in two equal parts.

A Line BD is called the angle bisector of $\angle ABC$ if

$\angle ABD = \angle CBD$

Please refer to image attached.

As per the question image, if the line PW is joined it will be the angle bisector of $\angle QPR$ .

Steps of construction of angle bisector:

1. Draw the angle QPR.

2. Open compass and make an arc that will cut the two lines on points Q and R respectively as shown in question figure.

3. With the same compass opening, put the compass on Q and make an arc in the area between $\angle QPR$ .

4. Draw an arc keeping the compass on R to cut the previous arc on point W.

Line joining the points P and W is the angle bisector of $\angle QPR$ .

So, Correct answer is option D) Construct the bisector of an angle.

6 0

3 years ago

Assume that adults have IQ scores that are normally distributed with a mean of 96 and a standard deviation of 15.7. Find the pro

astraxan [27]

Answer:

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 96, \sigma = 15.7$