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3 years ago

Give the positive solution of x^2 – 36 = 5x.

1 answer:

5 0

The equation given in the question is

x^2 - 36 = 5x
x^2 - 5x - 36 = 0
x^2 - 9x + 4x - 36 = 0
x(x - 9) + 4(x - 9) = 0
(x - 9) (x + 4) = 0
From the above set we can say that x = 9 is the positive solution of the equation given in the question. I hope that this is the answer that you were looking for and it has come to your great help.

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H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.

natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

<h3>Given information-</h3>

The given function is,

$h(x)=x^2+1$

$k(x)=x-2$

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

$(h+k)(x)=h(x)+k(x)$

$(h+k)(x)=x^2+1+x-2$

$(h+k)(2)=2^2+1+2-2$

$(h+k)(x)=5$

2)The value of the function (h-k)(3),

$(h-k)(x)=h(x)-k(x)$

$(h-k)(x)=x^2+1-x+2$

$(h-k)(3)=3^2+1-3+2$

$(h-k)(x)=9$

3) The value of the function 3h(2)+2k(3)

$3h(x)+2k(x)=3x^2+3+2x-2\times 2$

$3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2$

$3h(2)+2k(3)=17$

Hence the value of the given functions are,

$(h+k)(x)=5$

$(h-k)(x)=9$

$3h(2)+2k(3)=17$

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0

3 years ago

I have some cheese. I used

hram777 [196]

<h3>Answer: 2500 grams</h3>

============================================

Work Shown:

A = amount of grams of cheese you had originally

B = (2/5)*A = amount of cheese you use up after day 1

C = (3/5)*A = amount of cheese you have left over after day 1

note how B and C add back up to 'A'.

This is because 2/5+3/5 = 5/5 = 1, so,

B+C = (2/5)A+(3/5)A = (2/5+3/5)A = 1*A = A

--------------

D = (2/5)*C = amount of cheese you use up after day 2

E = (3/5)*C = amount of cheese left over after day 2

the variables D and E add up to C

we are told that there are 900 grams of cheese left after day 2, so E = 900

--------------

E = (3/5)*C

(3/5)*C = E

(3/5)*C = 900 ... Plug in E = 900

3C = 900*5 .... multiply both sides by 5

3C = 4500

C = 4500/3 .... divide both sides by 3

C = 1500

This means you had 1500 grams of cheese after day 1

-------------

C = (3/5)*A

(3/5)*A = C

(3/5)*A = 1500 ... plug in C = 1500

3A = 1500*5 ... multiply both sides by 5

3A = 7500

A = 7500/3 .... divide both sides by 3

A = 2500

-----------

<h3>You started off with 2500 grams of cheese.</h3>

After day 1, you use up (2/5)*2500 = 1000 grams of cheese and have 2500-1000 = 1500 grams left over.

After day 2, you use up (2/5)*1500 = 600 grams of cheese and have 1500-600 = 900 grams left over.

The answer is confirmed.

6 0

3 years ago

What is the slope of the line passing through the given points (1, -4) and (3, 2)?

bazaltina [42]

Answer: 1/3 would be the answer because the slope is positive.

5 0

3 years ago

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The zoo charges the Garcia family an admission fee of $5.25 per person

Anuta_ua [19.1K]

Answer:

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3 years ago