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maksim [4K]
4 years ago
15

Determine which compound would raise the boiling point of water the most

Chemistry
1 answer:
Olenka [21]4 years ago
8 0
All of the provided salts will increase the boiling point of water due to Boiling point elevation is considered as one of the colligative properties that only affected by the number of particles present in solution regardless their nature.

All of the choices are considered as electrolytes (ionizes in water) so the one which gives higher number of ions will raise the boiling point the most so the correct answer is A) AlCl₃ due to it ionizes to give 4 ions one Al and 3 Cl while NaCl gives only 2 ions, CaCl₂ gives 3 ions and KBr gives 2 ions 

So the correct answer is A) 2.0 M AlCl₃ 
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You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31 kilograms. How would you enter this number
mote1985 [20]

Answer:

The answer is the same as 9.11x10-31kg which is the mass of an electron,

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The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas
Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

PV=n_1RT

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

n_1 = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(9.61atm)\times (3.06L)=n_1\times RT

n_1=\frac{29.4}{RT}

Now we have to calculate the moles of oxygen gas.

PV=n_2RT

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

n_2 = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(1.75atm)\times (6.65L)=n_2\times RT

n_2=\frac{11.6}{RT}

Now we have to determine the final pressure in the system after mixing the gases.

P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}

where,

P_{total} = final pressure of gas = ?

V_{total} = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}

P_{total}=4.22atm

Therefore, the final pressure in the system is 4.22 atm.

4 0
3 years ago
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