Answer:
The answer is a I think
Explanation:
I think this because it has all of the shapes that are included in the other ones
<u>Answer:</u>
<u>Balancin</u>g is making the number of atoms of each element same on both the sides (reactant and product side).
To find the number of atoms of each element we multiply coefficient and the subscript
For example
contains
5 × 1 = 5,Ca atoms and
5 × 2 = 10, Cl atoms
If there is a bracket in the chemical formula
For example
we multiply coefficient
subscript
number outside the bracket.......... to find the number of atoms
(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )
So
3 × 3 = 9, Ca atoms
3 × 1 × 2 = 6, P atoms
3 × 4 × 2 = 24, O atoms are present.
So
Let us balance the equation given

(Unbalanced)
Reactant side - Number of atoms of each element - Product side
1 - Sb - 1
2 - Cl - 3
So we have on the product side odd number of Cl to convert to even number, multiply
by 2
The equation changes to

Reactant side - Number of atoms of each element - Product side
1 - Sb - 2
2 - Cl - 6
Multiplying Sb by 2 and 

The equation is balanced now!!!!
Reactant side - Number of atoms of each element - Product side
2 - Sb - 2
6 - Cl - 6
Balanced.
Answer:
[Fe(phen)3]2+ Reactants Fe+2 clear phen white solid product orange red
mol ratios 1;1 OF fE
Explanation:
Answer:
When pH = pKa, the ionizable compound in question (either acid or base) will be half protonated and half deprotonated
Explanation:
A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.
An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.
Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.
Answer:
Trichloromethane is your answer
Explanation: