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grandymaker [24]
3 years ago
14

A 500.0 g sample of an element at 153.0 °C is dropped into an ice-water mixture. 109.5 g of ice melts and there is still an ice

- water mixture. What is the specific heat of the metal in J/g-°C? Given the molar heat capacity of the metal is 26.31 J/mol °C, what is the atomic weight and identity of the metal?
Chemistry
1 answer:
Lilit [14]3 years ago
8 0

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wtjfavyw

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WE NAME BRAINLIEST PLZZ HELP
Wittaler [7]

Answer:

The answer is a I think

Explanation:

I think this because it has all of the shapes that are included in the other ones

4 0
3 years ago
Balance 6Sb +6Cl2– 6SbCl3
labwork [276]

<u>Answer:</u>

<u>Balancin</u>g is making the number of atoms of each element same on both the sides  (reactant and product side).

To find the number of atoms of each element we multiply coefficient and the subscript  

For example 5 Ca_1 Cl_2 contains

5 × 1 = 5,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example 3Ca_3 (P_1 O_4 )_2 we multiply coefficient \times subscript \times number outside the bracket.......... to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9, Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So

Let us balance the equation given

1Sb +1Cl_2 > 1SbCl_3

(Unbalanced)

Reactant side - Number of atoms of each element - Product side

1  - Sb - 1

2 - Cl - 3  

So we have on the product side odd number of Cl to convert to even number, multiply SbCl_3 by 2

The equation changes to

1Sb +1Cl_2> 2SbCl_3

Reactant side - Number of atoms of each element - Product side

1  - Sb - 2

2 - Cl - 6

Multiplying Sb by 2 and Cl_2

2Sb +3Cl_2> 2SbCl_3

The equation is balanced now!!!!  

Reactant side - Number of atoms of each element - Product side

2  - Sb - 2

6 - Cl - 6

Balanced.

4 0
3 years ago
Write the chemical equation for the reaction of Fe(II) ion (Fe2 ) with phenanthroline. (Use the abbreviation phen for the phenan
miskamm [114]

Answer:

[Fe(phen)3]2+    Reactants  Fe+2 clear phen white solid   product orange red

mol ratios 1;1 OF fE

Explanation:

8 0
3 years ago
The pKa for a weak acid to be used in the buffer should be as close as possible to the desired pH. What if the pKa is not close
nikdorinn [45]

Answer:

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Explanation:

A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.

An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.

Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.

3 0
4 years ago
Is CHCI3 an element or compound?
Art [367]

Answer:

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