Here's a rule that I learned from my algebra teacher almost 60 years ago. It's so handy, and I use it so often, that it's still fresh in my mind, and even though it's so old, it still works !
In fact, it's so useful that it would be a great item for you to memorize and keep in your math tool-box.
==> To factor the difference of two squares, write
<em>(the sum of their square roots) </em>times<em> (the difference of their square roots)</em> .
That's exactly what you need to solve this problem. I'll show you how it works:
<u>9x² - 25</u>
You look at this for a few seconds, and you realize that 9x² is the square of 3x , and 25 is the square of 5 . So this expression is the difference of two squares, and you can use the shiny new tool I just handed you.
The square roots are 3x and 5 .
So the factored form of the polynomial is <em>(3x + 5) (3x - 5)</em> .
That's all there is to it. If you FOIL these factors out, you'll see that you wind up with the original polynomial in the question.
the first thing to do is to add all like terms for example p+p would turn into p+p to make it so we can add them together which after we add both of those p's together we get p which now we have p+7=p+5+4 which now we add 5 and 4 which we get 9 which now the equation looks like p+7=p+9 which now we subtract 7 from 9 and we are left with 2 so now the equation is p=p+2 which now we subtract p from p and we are left with -p=2 which now we divide both sides by - which makes the equation look like p=2÷- which equals -6 so all we are left with is p=-6