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padilas [110]
3 years ago
8

How many 2-inch by 3-inch by 8-inch bricks will you need to build a (uniformly wide) brick walk with the shape shown in the figu

re below? (Lay the bricks so that the largest face is up. Assume that
Mathematics
1 answer:
Olenka [21]3 years ago
8 0
Idek what you are asking this is so wierd
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Im dying bro help The vertices of a quadrilateral are (2, 3), (3, 8), (7, 5), and (6, 2). Draw the quadrilateral in the coordina
Solnce55 [7]
Okay to the first number in the ordered pair is the x and the second is the y. So (x,y) when you put a dot on the coordinate plane such as (2,3), you have to go the the horizontal line which is x and go over right 2 spaces(depending on how many numbers is one space) then go up 3. Do that same thing for each of the order pairs. Eventually you will have 4 dots. Connect those dots then you will have the quadrilateral. I hope this helps you!
7 0
3 years ago
A country will produce 3000 missiles this year. Each of the short-range missiles cost $200000 to produce. Each of the medium-ran
Lynna [10]

Answer:

$350,000

Step-by-step explanation:

Let's define:

  • s: amount of short-range missiles produced
  • m: amount of medium-range missiles produced
  • l: amount of long-range missiles produced

From the total production and the ratios we can write the following equations:

s + m + l = 3000

s/m = 3/3 = 1 = m/s

s/l = 3/4 or l/s = 4/3

Dividing the first equation by s, we get:

s/s + m/s + l/s = 3000/s

1 + 1 + 4/3 = 3000/s

10/3 = 3000/s

s = 3000*3/10 = 900

m = 900

l =  4/3*900 = 1200

From the money that the countries plans to use and each missile cost, we can write the following equation:

200,000*s + 300,000*m + cost*l = 870,000,000

Replacing with previous result:

200,000*900 + 300,000*900 + cost*1200 = 870,000,000

cost = (870,000,000 - 200,000*900 - 300,000*900)/1200 = 350,000

3 0
3 years ago
Can someone plz help me with this
Levart [38]
D.
None of the above. Because your expression would be, 2 + 0.75 x 6.
Hope it helps. ;)
7 0
3 years ago
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
3 years ago
Jina wanted to study how the area of a rectangle changes with the length if it’s width is fixed. She computed the areas of sever
olganol [36]

Answer:

The domain and the range of the function are, respectively:

Dom\{f\} = [0\,m,5\,m]

Ran\{f\} = [0\,m^{2}, 10\,m^{2}]

Step-by-step explanation:

Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.

Dom\{f\} = [0\,m,5\,m]

Ran\{f\} = [0\,m^{2}, 10\,m^{2}]

8 0
3 years ago
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