To solve 7y > -161, we divide both sides by 7 and it leads to y > -23. The inequality sign does not flip in this case, because we are not dividing both sides by a negative number.

The similarities is that we end up with -23 on the right side, but the inequality signs are different.

5 0

2 years ago

HURRY I NEED HELP!!!!!!!!!!!!! A circle is drawn within a square as shown.

Anton [14]

The width of the square is 7 cm. This is also the diameter of the circle.

To find the area of the square, you do 7², which is 49 cm².

To find the area of a circle, you do πr².

The radius is half the diameter, so it's 7 ÷ 2, which is 3.5 cm.

π3.5² ≈ 38.4845100065 cm².

The shaded region is the area of the square minus the area of the circle.

49 - 38.4845100065 = <span>10.5154899935, but because you're using 3.14 to approximate pi, the closest answer is 10.54 cm</span>².

The answer is 10.54 cm².

3 0

2 years ago

Read 2 more answers

Jerome burns 4 cal/min walking and 10 cal/min running. He walks between 10 and 20 min each day and runs between 30 and 45 min ea

erik [133]

Answer:

20 minutes should spend on walking and 30 minutes on running.

Step-by-step explanation:

Let x represents the minutes spent on walking and y represents the minutes spent on running,

∵ He burns 4 cal/min walking and 10 cal/min running,

So, the total calories burnt,

Z = 4x + 10y

Which has to be maximised.

Now, he walks between 10 and 20 min each day,

i.e. 10 < x < 20,

Also, he runs between 30 and 45 min each day,

i.e. 30 < y < 45,

By graphing 10 < x < 20 and 30 < y < 45,

We obtained the vertices of feasible region,

(10, 45), (20, 45), (10, 30) and (20, 30)

At (10, 45),

Z = 4(10) + 10(45) = 40 + 450 = 490,

At (20, 45),

Z = 4(20) + 10(45) = 80 + 450 = 530,

At (10, 30),

Z = 4(10) + 10(30) = 40 + 300 = 340,

At (20, 30)

Z = 4(20) + 10(30) = 80 + 300 = 380

Hence, maximum calories is 530 when 20 minutes spent on walking and 30 minutes spent on running.

5 0

3 years ago