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3 years ago

145 in the ratio 18:11

Mathematics

1 answer:

Dmitrij [34]3 years ago

5 0

Answer:

90:55

Step-by-step explanation:

18 + 11 = 29

145/29 = 5

5 x 18 = 90

5 x 11 = 55

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Assume that there are 20 m&ms in a bowl (5 red, 11 yellow, 4 green).

Nina [5.8K]

You're a bot. If you aren't I'm sorry but your name is like the exact same as a bunch of others

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3 years ago

Calculate the specified probability Suppose that K is a random variable. Given that P(-2.2 ≤ K ≤ 2.2) = 0.725, and that P(K <

belka [17]

Answer:

P(K > 2.2) = 0.1375

Step-by-step explanation:

We have that:

P(-2.2 ≤ K ≤ 2.2) = 0.725

P(K < -2.2) = P(K > 2.2)

It means that the distribution is symmetric.

The sum of all the probabilities is decimal 1.

We have the following probabilities:

P(K < 2.2)

P(-2.2 ≤ K ≤ 2.2)

P(K > 2.2)

P(K < 2.2) + P(-2.2 ≤ K ≤ 2.2) + P(K > 2.2) = 1

Since P(K < 2.2) = P(K > 2.2)

P(K > 2.2) + P(-2.2 ≤ K ≤ 2.2) + P(K > 2.2) = 1

2P(K > 2.2) + 0.725 = 1.

2P(K > 2.2) = 1 - 0.725

2P(K > 2.2) = 0.275

P(K > 2.2) = 0.275/2

P(K > 2.2) = 0.1375

6 0

3 years ago

a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer.

miss Akunina [59]

Answer:

$\frac{1}{990}$

Step-by-step explanation:

The full question:

"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = $\frac{n!}{(n-r)!}$

Where n would be the total [in this case n is 11] & r would be 3

Which is:

P(11,3) = $\frac{11!}{(11-3)!}=\frac{11!}{8!}=11*10*9=990$

So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:

1/990

8 0

3 years ago

There are 160 students in the seventh grade, and 10% are in the

Julli [10]

Answer:

Step-by-step explanation:

Turn 10% into a decimal, so 0.1

160 x 0.1 = 16

7 0

2 years ago

Read 2 more answers

How do you solve this? Y x 49/36=7/12

Triss [41]

Divide both sides by 49/36 to get y by itself:

$\frac{7}{12} \div \frac{49}{36}$

$\frac{7}{12} \times \frac{36}{49} = \frac{254}{588}$

Simplify this fraction:

$\frac{254}{588} \div \frac{2}{2} = \frac{127}{294}$

Now you have your answer:

$y = \frac{127}{294}$

5 0

3 years ago