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sweet-ann [11.9K]
3 years ago
11

If a school cafeteria needs c cans of soup each week for each student, and if there are s students in the school, for how many w

eeks will x cans of soup last?
Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
6 0

Answer:

\frac{x}{c*s} weeks

Step-by-step explanation:

SO in order to calculate that you need to first multiply the number of cups of soup a week by student that the cafeteria need, by the number of students, so if you have S number of student and each needs C amount of cups of soup, the cups of soup total will be CS.

So in order to know how many weeks will X number of cups will last you just divide the number of cups by CS:

\frac{x}{c*s} weeks

And that´s the answer.

Sphinxa [80]3 years ago
4 0

Answer:

x/(cs)

Step-by-step explanation:

Let w represent the number of weeks we're feeding students soup.

w\,\text{weeks}\times\dfrac{c\,\text{cans}}{\text{student}\cdot\text{week}}\times s\,\text{students}=x\,\text{cans}\\\\w=\dfrac{x}{c\cdot s}\qquad\text{divide by $c\cdot s$}

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Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
Do more than 50 percent of the children in a certain group have brown hair?
babymother [125]

Answer:

What we know is that 30% of the group have brown hair and are girls. It means that in the other 70% we have the boys with brown hair, the other boys and the other girls.

In the case all the girls have brown hair, the 70% remaining would be boys. So 70% of then would have brown hair. (0.7*0.7=0.49 -> 49% of the children would be brown hair) so 49% (boys) and 30% (girls) are more than 50%..

Now, let's suppouse that 90% of the group are girls. It means 10% are boys and 70% of that 10% (=7%) are the boys in the group that have brown hair. Now 7% + 30% of the children have brown hair, wich isn't more than the half.

We have explained with two extreme cases that the information is not enough for making a precise answer

7 0
3 years ago
A members-only speaker series allows people to join for $28 and then pay $4 for every event attended. What is the total cost for
wariber [46]

Given:

Joining fee = $28

Fee of each event = $4

To find:

Total cost for someone to attend 4 events.

Solution:

Let the number of events be x and total fee be y.

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y=28+4x

Substitute x=4 in this equation.

y=28+4(4)

y=28+16

y=44

Therefore, total cost of 4 events is $44.

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Answer:

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Step-by-step explanation:

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