Question

During the semester, all the students in a statistics class kept track of the number of mailings they received from a predatory payday lender. The count for each is displayed below: Student Bob Sue Pam Lee Mary Carl Ace Moe Ann Mailings 16 17 11 21 15 14 17 18 19 The 75th percentile for the number of mailings for these students is:

Answer 1

Answer:

The first step on this case is order the dataset on increasing way, and after do this we got:

11 14 15 16 17 17 18 19 21

We have a sample size of n =9

And in order to find the 75th percentile we need to find the position for this percentile with this formula:

$n_{75} = 0.75* 9= 6.75\approx 7$

So then we can conclude that the 75th percentile would be approximately on the 7 position of the dataset ordered and we got:

$x_{75} = 18$

Step-by-step explanation:

For this case we have the following data:

16 17 11 21 15 14 17 18 19

The first step on this case is order the dataset on increasing way, and after do this we got:

11 14 15 16 17 17 18 19 21

We have a sample size of n =9

And in order to find the 75th percentile we need to find the position for this percentile with this formula:

$n_{75} = 0.75* 9= 6.75\approx 7$

So then we can conclude that the 75th percentile would be approximately on the 7 position of the dataset ordered and we got:

$x_{75} = 18$