Answer:
the coordinates of point B are (-5, 2)
Step-by-step explanation:
1. use midpoint formula to find the midpoint (equation attached below)
2. plug in the numbers

3. solve



Answer:
We know that the rectangular plate has measures of:
length = 7.6 ± 0.05 cm
width = 3.1 ± 0.05 cm
(the error is 0.05cm because we know that both measures are correct to one decimal place)
First, the upper bound of the length is equal to the measure of the length plus the error, this is:
L = 7.6 cm + 0.05 cm = 7.65 cm
The upper bound of the area is the area calculated when we use the upper bound of the length and the upper bound of the widht.
Remember that the area for a rectangle of length L and width W, is:
A = W*L
Then the upper bound of the area is:
A = (7.6cm + 0.05cm)*(3.1cm + 0.05cm) = 10.8 cm^2
Answer:
Table 3
Step-by-step explanation:
Check table three;


Since the left hand limit
is not equal to the right hand limit
, the limit as x approaches to 2 does not exist.
Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2
Answer: 306 inches or 25.5 feet or 8.5 yards.
Step-by-step explanation:
Given: Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of ribbon.
1 feet = 12 inches
length of ribbon Tino has = 12 x 7.5 = 90 inches
1 yard = 36 inches
length of ribbon Baxter has = 3.5 x 36 = 126 inches
Total ribbon they have = (length of ribbon Carol has) + (length of ribbon Tino has) + (length of ribbon Baxter has)
= (90+90+126) inches
= 306 inches
In feet , Total ribbon =
![[\text{ 1 inch}=\dfrac{1}{12}\text{ feet}]](https://tex.z-dn.net/?f=%5B%5Ctext%7B%201%20inch%7D%3D%5Cdfrac%7B1%7D%7B12%7D%5Ctext%7B%20feet%7D%5D)

In yards, Total ribbon =
![[\text{1 feet}=\dfrac{1}{3}\text{ yard}]](https://tex.z-dn.net/?f=%5B%5Ctext%7B1%20feet%7D%3D%5Cdfrac%7B1%7D%7B3%7D%5Ctext%7B%20yard%7D%5D)

Hence, the total length of ribbon the three friends have is 306 inches or 25.5 feet or 8.5 yards.