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Ludmilka [50]
4 years ago
9

Which system below has no solution? y = 4x and y = 2x - 3y = -4x and y = 2x - 3 y = -4x and y = 2x + 3

Mathematics
1 answer:
Gnom [1K]4 years ago
5 0

Answer:

25

Step-by-step explanation:

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Find the sum of the first terms of the sequence
Free_Kalibri [48]

Answer:

-4+8+-16+32+-64+128 = 84

Step-by-step explanation:

The fifth and sixth terms are -64 and 128

4 0
3 years ago
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RHOMBUS The diagonals of rhombus ABCD intersect at E. Given that
schepotkina [342]

Answer:

<u>Question 11:</u>

\angle DAC = 53^\circ

\angle AED = 90^\circ

\angle ADC = 74

DB = 16

AE = 6.03

AC = 12.06

<u>Question 12:</u>

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

Step-by-step explanation:

<u>Question 11</u>

Given

\angle BAC = 53^\circ

DE = 8

See attachment for Rhombus

Required

Determine the indicated sides

Solving (a): \angle DAC

Diagonal CA divides \angle DAB into 2 equal angles

i.e

\angle DAC = \angle BAC

So:

\angle DAC = 53^\circ

Solving (b): \angle AED

The angles at E is 90 degrees because diagonals AC and BD meet at a perpendicular.

So:

\angle AED = 90^\circ

Solving (c): \angle ADC

First, we calculate \angle ADE, considering \triangle ADE:

\angle ADE + \angle AED + \angle DAC = 180

\angle ADE + 90 + 53 = 180

\angle ADE + 143 = 180

\angle ADE = -143 + 180

\angle ADE = 37

To calculate \angle ADC, we have:

\angle ADC = 2*\angle ADE

\angle ADC = 2* 37

\angle ADC = 74

Solving (d): DB

From the rhombus

DB = DE +EB

Where

DE =EB

So:

DB = 8 + 8

DB = 16

Solving (e): AE

To do this we consider \triangle ADE

Using the tan formula

tan(\angle ADE) = \frac{AE}{DE}

\angle ADE = 37 and DE = 8

So:

\tan(37) = \frac{AE}{8}

AE = 8 * \tan(37)

AE = 6.03

Solving (f): AC

This is calculated as:

AC = AE + EC

Where

AE = EC

AC = 6.03 +6.03

AC = 12.06

<u>Question 12: Isosceles Triangle</u>

In the rhombus, all 4 sides are equal;

So, the isosceles triangle are:

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

4 0
3 years ago
Kathy swims at least 6 laps every day. Write an
umka2103 [35]

Step-by-step explanation:

she swims at least 45 min's a day

4 0
4 years ago
One year ago, Clare was 4 feet 6 inches tall. Now, Clare is 4 feet 10 inches tall. By what percentage did Clare's height increas
DaniilM [7]
7.4% increase of height
6 0
3 years ago
I need help on number 9
umka21 [38]

Answer:


Step-by-step explanation:

You used Pythagorean theroem which is correct as this does form a right triangle however 50 is the hypotenuse as the ladder is propped up against the wall. 30 would then be the height of the triangle and the base is unknown so...

50^{2} = 30^{2} + x^{2}

50 squared minus thirty squared gives 1600 so:

1600 = x^{2}

Therefore x is the square root of 1600 which is 40

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3 years ago
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