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1 year ago

Here is the proof of sinx+cos^2x/cosx=tanx+cosx. What is the missing line?

Mathematics

1 answer:

Eva8 [605]1 year ago

3 0

See Explanation Below

Step-by-step explanation:

Given

Required

Prove

To start with; we open the bracket on the left hand side

Reorder

From trigonometry;

So;

becomes

Also from trigonometry;

So,

becomes

Proved

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Find the area of an equilateral triangle with a side of 6 inches.

sweet-ann [11.9K]

Answer:

9 $\sqrt{3}$ in²

Step-by-step explanation:

The area (A) of an equilateral triangle is calculated as

A = $\frac{s^2\sqrt{3} }{4}$ ( s is the length of a side )

Here s = 6, thus

A = $\frac{6^2\sqrt{3} }{4}$ = $\frac{36\sqrt{3} }{4}$ = 9 $\sqrt{3}$ in²

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2 years ago

For a population with µ = 80 and σ = 20, the distribution of sample means based on n = 16 will have an expected value of _______

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4 months ago

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lorasvet [3.4K]

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Step-by-step explanation:

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2 years ago

Solve the equation -25p – 2 = 48 for p. A. -2 B. 1 C. 3 D. 8

konstantin123 [22]

Answer:

A. -2

Step-by-step explanation:

-25p - 2 = 48

First, add 2 to both sides

That gives you

-25p = 50

Then, divide both sides by -25. Then that leaves the answer.. p = -2

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2 years ago

How would I do the steps to solve this?

allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

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2 years ago