Answer:
Step-by-step explanation:
GIVEN: A farmer has 
of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 
.
TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.
SOLUTION:
Let the length of rectangle be 
and 
perimeter of rectangular pen 
area of rectangular pen 
putting value of
to maximize 
but the dimensions must be lesser or equal to than that of barn.
therefore maximum length rectangular pen 
width of rectangular pen 
Maximum area of rectangular pen 
Hence maximum area of rectangular pen is 
and dimensions are
Answer:
Assignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
Step-by-step explanation:
Assignment: 01.07 Laboratory Techniques
Assignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
The schools is loacted at <u>(1, -8)</u> and the park is loacted at <u>(-6,-8)</u>
Here's the way I see it: 5 cards are drawn, one by one, without replacement. Half (or 26) of the original deck are black and half (26) are white.
P(5 are not black) = P(5 are red)
P(5 are not black) = P(first card is red) * P(second card is red) * P(third card is red)*P(fourth card is red)*P(fifth card is red) =
(26/52) * (25/51) * (24/50) * (23/49) * (22/48) = 0.025 (answer)
We start with 52 cards. We draw one, leaving 51 cards, 25 of which are red. And so on.
Answer:hellos 6
Step-by-step explanation:
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