Question

Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°.

Answer 1

ANSWER

36√3 square units.

EXPLANATION

The area of a parallelogram is obtained by multiplying the base by the height.

We use the sine ratio to obtain the height.

$\sin(60 \degree) = \frac{h}{6}$

$h = 6 \sin(60 \degree)$

$h = 3 \sqrt{3}$

The area becomes:

$12 \times 3 \sqrt{3} = 36 \sqrt{3} {units}^{2}$