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3 years ago

11 12 13 Please help! Will reward brainliest

Mathematics

1 answer:

RoseWind [281]3 years ago

3 0

11. 9/20
12. 13/20
13. 12/20

that's if it doesn't have to be in percentage form

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Quick anyone know the answer?

den301095 [7]

The sum of the measures of angles in all quadrangles is 360 °. Therefore:

$(25x+1)+(25x-2)+(20x-1)+82=360\\\\70x+80=360\ \ \ |-80\\\\70x=280\ \ \ |:70\\\\x=4$

$m\angle D=(20x-1)^o\to m\angle D=(20\cdot4-1)^o=79^o\\\\Answer:\ B.\ 79^o$

8 0

3 years ago

The surface area of a rectangular prism is 208 cm. Two of the dimensions are 2cm and 10 cm. Find the measure of the other dimens

kompoz [17]

2 times 10 equals 20

208 divided by 20 equals 10.4

6 0

3 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sauron [17]

The test statistic for the hypothesis would be 1.413.

Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.

The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.

Hypothesis:

Null hypothesis:H₀:μ=13

Alternative hypothesis:Hₐ:μ>13

Here, μ be the mean weight loss of all participants.

n=30,

Degree of freedom n-1=30-1=29

$\bar{x}$ =13.8 and s=3.1

To test the null hypothesis H₀, the value of test static would be calculated as follows:

$\begin{aligned}t&=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}}}\\ t_{29}&=\frac{13.8- 13}{\frac{3.1}{\sqrt{30}}}\\ &=\frac{0.8}{0.566}\\ &=1.413\end$

Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.

Learn more about hypothesis from here brainly.com/question/14783359

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6 0

2 years ago

If a certain cannon is fired from a height of 8.8 meters above the ground, at a certain angle, the height of the cannonball ab

Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

$h(t)=-4.9t^2+30.5t+8.8$

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

$-4.9t^2+30.5t+8.8=0$

Multiply both sides by 10.

$-49t^2+305t+88=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a = -49, b = 305 and c=88

$t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}$

Ignore the negative value of t as time can't be a negative number.

Thus,

$t=\frac{305+\sqrt{110273}}{98}\approx6.50$

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0

3 years ago

3x−8 ≤ 23 OR −4x+26≥6 find x

ElenaW [278]

Answer:

3x-8<=23

3x<=23+8

3x< =31

X< = 10.3

-4x+26>=6

-4x>=-20

X>=5

6 0

3 years ago