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lana [24]
3 years ago
5

Lincoln has set up a lemonade stand outside his house and sells small cups and large cups of lemonade. Each small cup holds 6 ou

nces of lemonade and each large cup hold 18 ounces of lemonade. Lincoln used 780 ounces of lemonade and sold 4 times as many large cups as small cups. Write a system of equations that could be used to determine the number of small cups sold and the number of large cups sold. Define the variables that you use to write the system.
Mathematics
1 answer:
max2010maxim [7]3 years ago
5 0

Answer: The system of equations that could be used to determine the number of small cups sold and the number of large cups sold is

6x + 18y = 780

y = 4x

Step-by-step explanation:

Let x represent the number of small cups that were sold.

Let y represent the number of large cups that were sold.

Each small cup holds 6 ounces of lemonade and each large cup hold 18 ounces of lemonade. Lincoln used 780 ounces. This is expressed as

6x + 18y = 780- - - - - - - - - - 1

Lincoln sold 4 times as many large cups as small cups. This is expressed as

y = 4x

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What are the possible values of x in 8x2 + 4x = -1?
Westkost [7]

Answer:

The possible values of x are:

x= \frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18

and

x= \frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68

Step-by-step explanation:

8x^2+4x+1=0

Using Quadratic formula to solve this equation:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a = 8 \,\, b = 4\,\, c = -1\\Putting \,\, values \,\, in \,\, the\,\, equation\\x= \frac{-4\pm\sqrt{(4)^2-4(8)(-1)}}{2(8)}\\x= \frac{-4\pm\sqrt{16+32}}{16}\\x= \frac{-4\pm\sqrt{48}}{16}\\x= \frac{-4+ \sqrt{48}}{16} \,\, and \,\, x= \frac{-4- \sqrt{48}}{16}\\x= \frac{-1+ \sqrt{3}}{4} \,\, and \,\, x= \frac{-1- \sqrt{3}}{4}

The possible values of x are:

x= \frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18

and

x= \frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68

4 0
3 years ago
The length of a rectangle is (x + 1) cm and its width is 5cm less than its length.
NeX [460]

Answer:

a) the area of a square is in terms of x is

(x+1)^2 centimeter square

b)The length of the rectangle is l = (x+1)

                                       l = 7+1 =8 cm

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 =3 cm

Step-by-step explanation:

a) the area of a square is in terms of x is

 area of square is l^{2} = (x+1)(x+1)

                                 = (x+1)^2

b)  Given length is  l = (x+1) cm and

the width is 5 cm less than its length.

so we have take width is w = (x+1)-5 cm

Given area of triangle is  24 cm

Area of rectangle = length X width

24  =  (x+1)(x+1 -5 )

now simplification 24 = (x+1)^2 - 5 (x+1)

apply (a+b)^2 = a^2+2 a b+b^2

x^2+2 x+1-5 x-5 =24

x^2 -3 x -4-24=0

x^{2} -3 x -28 =0

now find factors of 28  = 7 X 4 is  

x^{2} -7 x+4 x-28=0

x(x-7)+4(x-7)=0

(x+4)(x-7)=0

x = -4 and x=7

there fore you have to choose x = 7

The length of the rectangle is l = (x+1)

                                       l = 7+1 =8

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 = 3

<u>Verification:-</u>

Given area of rectangle  = 24 = 8 X 3

                                           24 =24

so we can not choose x=-4

we have to choose x =7 only

7 0
3 years ago
Can someone tell me whats1+1​
Andreyy89

Answer:

2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can yall please help me, try to explain in steps, tyy
almond37 [142]

Answer:

b. would be the answer bc it goes in a line if you were to connect the dots

8 0
3 years ago
Matteo is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satelli
natka813 [3]

Answer: (1.5, 0)

Step-by-step explanation:

Given : The shape of his satellite can be modeled by y^2=6x where x and y are modeled in inches.

Now,the given equation y^2=6x is a equation of parabola.

Here, coefficient of x is positive, hence the parabola opens rightwards.

On comparing this equation with standard equation x^2=4mx, we get

4m=6\\\Rightarrow\ m=\frac{6}{4}=1.5

In standard equation, coordinates of focus=(m,0)

Thus for given equation coordinates of focus=(1.5,0)

4 0
3 years ago
Read 2 more answers
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