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irina1246 [14]
3 years ago
6

3/x^2-1 - 2(x+3) = 5/x+1

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

X=1.132589

Step-by-step explanation:

If im correct the answer would be x=1.132589

3

x2−1

−2(x+3)=

5

x+1

3

(x+1)(x−1)

+−2x−6=

5

x+1

Multiply all terms by (x+1)(x-1) and cancel:

3+(−2x−6)(x+1)(x−1)=5(x−1)

−2x3−6x2+2x+9=5x−5(Simplify both sides of the equation)

−2x3−6x2+2x+9−(5x−5)=5x−5−(5x−5)(Subtract 5x-5 from both sides)

−2x3−6x2−3x+14=0

(Use cubic formula)

x=1.132589

And dont forget to check your answer

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Answer:

9$ per hour

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Solve the equation<br> 4.8y-6.9=3.18<br> Explain your thinking
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4.8y - 6.9 = 3.18 
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Hope this helps!!
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3 years ago
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Choose the best score on a quiz. 24 points out of 42 24 points out of 42 75 points out of 135 75 points out of 135 150 points ou
stellarik [79]

Answer:

150/250

Step-by-step explanation:

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The population of a community is known to increase at a rate proportional to the number of people present at time t. If the popu
Lady bird [3.3K]

Answer:

P(t) = P(0)e^{0.0693t}

Step-by-step explanation:

The population of a community is known to increase at a rate proportional to the number of people present at time t.

This means that the population growth is modeled by the following differential equation:

\frac{dP(t)}{dt} = rP(t)

Which has the following solution:

P(t) = P(0)e^{rt}

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

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This means that P(10) = 2P(0). We use this to find r.

P(t) = P(0)e^{rt}

2P(0) = P(0)e^{10r}

e^{10r} = 2

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10r = \ln{2}

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r = 0.0693

So the equation that will estimate the population of the community in t years is:

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