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3 years ago

PLZ HELP, WILL GIVE BRAINLIEST

Mathematics

1 answer:

guajiro [1.7K]3 years ago

6 0

Answer:

x = C, 35

Step-by-step explanation:

This involves two steps. First, you have to know that all the angles of a triangle add up to 180. So the first thing we do is find the angle of the whole red part. 180 - 73 - 51 = 56. Then, we have that one of the angles near it is 21 and the other angle is x. To find x, we do 51 - 21 = 35. Therefore, 35 = x.

Thanks for brainliest! :D

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I have to right a statistic question would this be one Out of 60 7th graders 45 or 75% of them prefer to play sports after schoo

mina [271]

Answer:

This really isn't a question. I can help you out with writing one.

John randomly selected 45% of seventh grade students in his school and asked them what their favorite time to play sports was. Of the students surveyed, 51 prefer to play sports after school. Based on this data, what is the most reasonable prediction of seventh graders in his entire grade?

Step-by-step explanation:

To answer my question, you would set up a proportion.

$\frac{9}{20} = \frac{51}{x}$ <-- the answer to that question will will be 113.

5 0

4 years ago

suppose you flip a coin twice. what is the probability that you get tails on the first flip and tail on the second flip?

Nezavi [6.7K]

The possibilities are HH TT HT TH so to get TT you have a 1/4 chance (25%)

4 0

3 years ago

Read 2 more answers

Suppose the height of an 18 year old boy is normally distributed with mean 187cm fifteen percent of 18 year old boys have height

BARSIC [14]

Answer:

the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403

Step-by-step explanation:

P( x > 193) = 0.15

= 1- p(x less than or equal 193)

= 1 -p( z < (x- u) /sigma)

= 1- p( z< (193 - 187)/ sigma)

= 1- p( z< 6/ sigma)

P(z< 6/sigma) = 1 - 0.15

P(z < 6/sigma)= 0.85

6/sigma =1.036

Sigma= 6/1.036

Sigma= 5.79

P( x> 185) = 1- p( x< 185)

= 1- p (z < (185- 187)/5.79)

= 1- p( z< -0.345)

= 1- 0.365

= 0.635

P (x> 185) = 0.635 × 0.635

=0.403

3 0

4 years ago

Jonathan took 33 pictures on the class trip and 67

Semenov [28]

Answer:

JONATHAN WILL NEED 14 PAGES.

Explanation:

33 + 67 = 100

100 - 12 = 88

88 ÷ 6 = 14.6666667

14.6666667 ⇒ 14

(Round 14.6666667 down to 14 because Johnathan does not have .6666667 of a page.)

3 0

3 years ago

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
Then for the x direction it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, for the y direction, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

8 0

3 years ago