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3 years ago

The square root of 60 is between A) 5 and 6. B) 6 and 7. C) 7 and 8. D) 8 and 9.

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

6 0

c the square root is 7.7

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What is the length of the hypotenuse in a right triangle with legs of length 7 and 24?

Fiesta28 [93]

A² + b² = c² a and b are the legs and c is the hypotenuse.

7² + 24² = c²

49 + 576 = c²

625 = c²

√625 = √c²

25 = c

hope that helps, God bless!

4 0

3 years ago

The square root of 27 lies between which two whole numbers

Agata [3.3K]

Answer:

5 and 6

Step-by-step explanation:

The square root of 27 is 5.19615242271 , which is more than 5 but less then 6, therefore is between 5 and 6.

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<em>Hope this helped (: Can you please mark as brainliest?</em>

7 0

3 years ago

What’s the answer to (-8x) + x + (-2x)

Tresset [83]

$(-8x) + x + (-2x) = -8x + x - 2x = -9x$

8 0

3 years ago

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How do I graph the solution

notsponge [240]

Make the circle closed and the > needs to be underlined

8 0

3 years ago

Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree

kompoz [17]

Answer:

The 6th degree polynomial is $p(x) = (x-1)^3(x-4)^2(x+3)$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zero 1 with multiplicity 3.

$p(x) = (x-1)^3$

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

$p(x) = (x-1)^3(x-4)^2$

Zero -3 with multiplicity 1:

Considering the previous zeros:

$p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)$

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is $p(x) = (x-1)^3(x-4)^2(x+3)$

8 0

3 years ago