Answer:
No, because it does not have a constant rate of change.
Step-by-step explanation:
On the <em>x</em><em> </em>side of the table, there is a constant rate of change (+1). However, on the y side, it is not. The first change is +7, the next +5, and the last +6. The rate of change has to be constant on both sides for the table to be considered linear.
I would’ve guess it’s 10+20=10+20 since you didn’t show no pic :|
Linear: third graph from the left
Quadratic: fourth graph from the left
Exponential: first graph from the left
To find this out, look at the type of graft and then its factors.
Remark
You'll see it a whole lot easier if you make a substitution so that it looks like something you have already seen
Solution
let y = x^2
x^4 = x^2 * x^2
x^4 = y * y
x^4 = y^2
Now the expression becomes
y^2 + 8 y - 9 = z
(y + 9)(y - 1) = z
Now put the x^2 back in.
(x^2 + 9) ( x^2 - 1) = z
x^2 - 1 becomes x + 1 and x - 1. At this level x^2 + 9 can't be factored.
Answer
(x^2 + 9) (x + 1)(x - 1)
28.9 I think is this, I hope this help
