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Whitepunk [10]
3 years ago
11

What is the completely factored form of x^4+8x^2-9

Mathematics
2 answers:
abruzzese [7]3 years ago
6 0

Answer:(x+1)(x-1)(x^2+9)

Step-by-step explanation:

denis-greek [22]3 years ago
3 0

Remark

You'll see it a whole lot easier if you make a substitution so that it looks like something you have already seen

Solution

let y = x^2

x^4 = x^2 * x^2

x^4 = y * y

x^4 = y^2

Now the expression becomes

y^2 + 8 y - 9  =  z

(y + 9)(y - 1) = z

Now put the x^2 back in.

(x^2 + 9) ( x^2 - 1) = z

x^2 - 1 becomes x + 1 and x - 1. At this level x^2 + 9 can't be factored.

Answer

(x^2 + 9) (x + 1)(x - 1)


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