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gregori [183]
3 years ago
7

Use the distributive property write an equivalent expression. 26 + 2.9 =

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0
28.9 I think is this, I hope this help
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How do i solve this?
Hunter-Best [27]

Step-by-step explanation:

You need to solve for x.

You can do that by either setting both of the equations equal to each other. or Solve each one separately and subtract the EG equation from the EW to get GW

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2 years ago
Answer the math question correctly and look at the picture.
Mashcka [7]

the answer of this question is 6×10 6

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Step-by-step explanation:

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3 years ago
A customer visiting the suit department of a certain store will purchase a suit with probability 0.22, a shirt with probability
Pachacha [2.7K]

Answer:

a. The probability that a customer purchase none of these items is 0.49

b. The probability that a customer purchase exactly 1 of these items would be of 0.28

Step-by-step explanation:

a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:

let A represents suit

B represents shirt

C represents tie

P(A) = 0.22

P(B) = 0.30

P(C) = 0.28

P(A∩B) = 0.11

P(C∩B) = 0.10

P(A∩C) = 0.14

P(A∩B∩C) = 0.06

Therefore, the probability that a customer purchase none of these items we would have to calculate the following:

1 - P(A∪B∪C)

P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)

= 0.22+0.28+0.30-0.11-0.10-0.14+0.06

= 0.51

Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49

The probability that a customer purchase none of these items is 0.49

b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:

= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2  P(A ∩ B ∩ C))

=0.51 -0.23 = 0.28

The probability that a customer purchase exactly 1 of these items would be of 0.28

6 0
3 years ago
The sum of 5 consecutive integers is 120. What is the third number in this sequence?
aliina [53]
Ok so

x - the smallest
The other 4 are : x+1, x+2, x+3, x+4
We know that sum is 120
So
x+x+1+x+2+x+3+x+4=120
Combine like terms
5x+10=120
Subtract 10 on both sides
5x=120-10
5x=110
Divide by 5 on both sides
X=22
The third number is x+2 = 22+2=24

3 0
3 years ago
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