Answer:
D
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
If m > 0 , then line slopes upwards from left to right
If m < 0 , then line slopes downwards from left to right
y = 3x - 2
has m > 0 and c = - 2 , thus line slopes upwards crossing the y- axis at - 2
y = - 2x + 3
has m < 0 and c = 3, thus line slopes downwards crossing the y- axis at 3
on the graph this is the lower blue line and the red line
the solution to the system is at the point of intersection of the 2 lines
This is at point D
<h3>
Answer: Choice D) </h3>
Work Shown:

We must require that
and
to avoid having 0 in the denominator. This is why choice D is the answer.
Answer:
π/4
Step-by-step explanation:
x is the variable
-1 inverts the curve
π/4 is the phase shift or x axis offset
2 is the y axis offset