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4 years ago

Cheryl paid $37.20 for 12 gallons of ice cream for a school picnic. How much would 1 quart of ice cream cost?

2 answers:

7 0

First, you need to get to one gallon, which is 37.20 divided by 12. (3.1)
Divide that number by four, which is: 0.775, or 0.78 rounded up to the nearest hundredth.
Hope that helped.

Ronch [10]4 years ago

7 0

Remember that we had to cover 12 gallons into quarts, so we did 12 x 4 = 48 quarts. SO THE ANSWER WOULD BE... Divide $37.20 by 48... AND IT WOULD GET YOU O.78

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A mother explains to her child that the price on the sign is not the total price for an oil painting, because the price does not

dlinn [17]

Answer:

Or u cld simply just say 945 - 875 = 70

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2 years ago

X^4-28x^2=0 solve algebraically

Paha777 [63]

$x^4 - 28x^2 = 0$

$x^2(x^2 - 28) = 0$

$x^2 = 0 \ \ or \ \ (x^2 - 28) = 0$

$x = 0 \ \ or \ \ x^2 = 28$

$x = 0 \ \ or \ \ x = \pm \sqrt{28}$

$x = 0 \ \ or \ \ x = \pm2 \sqrt{7}$

---------------------------------------------------
Answer : x = 0 or 2√7 or -2√7
---------------------------------------------------

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3 years ago

What is x in 10(x-2)= -20

MatroZZZ [7]

Answer:

x = 0

Step-by-step explanation:

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3 years ago

Read 2 more answers

An isosceles triangle has side lengths of 15.6 units and 20.33 units. What is the greatest possible value of the perimeter of th

ArbitrLikvidat [17]

Answer:

56.26

Step-by-step explanation:

An isosceles triangle has two sides that are the same length, and one side that is the same length. We have two sizes, so two find the greatest possible perimeter we must assume that the greater size is the value for the two sides, and the smaller size the value for the single side. In other words:

$x = 15.6 + 2(20.33)$

$x = 56.26$

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2 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

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3 years ago