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d1i1m1o1n [39]
3 years ago
5

Cheryl paid $37.20 for 12 gallons of ice cream for a school picnic. How much would 1 quart of ice cream cost?

Mathematics
2 answers:
Stells [14]3 years ago
7 0
First, you need to get to one gallon, which is 37.20 divided by 12. (3.1)
Divide that number by four, which is: 0.775, or 0.78 rounded up to the nearest hundredth.
Hope that helped.
Ronch [10]3 years ago
7 0
Remember that we had to cover 12 gallons into quarts, so we did 12 x 4 = 48 quarts. SO THE ANSWER WOULD BE... <span>Divide $37.20 by 48... AND IT WOULD GET YOU O.78</span>
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A 15 foot building casts a 9 foot shadow. How tall is the building if it casts a 30 foot shadow at the same time?
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There is triangle one of the angles is 101 degrees and the other is 38 workout x
Wittaler [7]

Angle sum property = Sum of the three angles of a triangle will be equal to 180° .

Using this let us find out the measure of x .

Measure of first angle = 101°

Measure of second angle = 38°

Measure of third angle = x

101 + 38 + x = 180

139 + x = 180

x = 180 - 139

= x = 41

∴ \: the \: value \: of \: x \:  = 41°

8 0
3 years ago
Find x to the nearest hundredth place.
Arada [10]

Answer:

C.  24.27 cm

Step-by-step explanation:

sin 65° = opposite ÷ hypotenuse

sin 65° = 22/x

multiply both sides of the equation by x

(sin 65°)x = 22

divide both sides of the equation by sin 65°

x = 22 ÷ sin 65°

punch in 65 sin into your calculator

x = 22 ÷ 0.90631

x = 24.27 cm

7 0
2 years ago
Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
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