Can't answer without a picture
it takes 3 years.formula interest =PRT/100 so its 252 =1200 times 7 times T all over 100 then multiply by 100 both sides to get 25200=8400T devide by 8400 both sides to get 3
Answer:
(identity has been verified)
Step-by-step explanation:
Verify the following identity:
sin(x)^4 - sin(x)^2 = cos(x)^4 - cos(x)^2
sin(x)^2 = 1 - cos(x)^2:
sin(x)^4 - 1 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2
-(1 - cos(x)^2) = cos(x)^2 - 1:
cos(x)^2 - 1 + sin(x)^4 = ^?cos(x)^4 - cos(x)^2
sin(x)^4 = (sin(x)^2)^2 = (1 - cos(x)^2)^2:
-1 + cos(x)^2 + (1 - cos(x)^2)^2 = ^?cos(x)^4 - cos(x)^2
(1 - cos(x)^2)^2 = 1 - 2 cos(x)^2 + cos(x)^4:
-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = ^?cos(x)^4 - cos(x)^2
-1 + cos(x)^2 + 1 - 2 cos(x)^2 + cos(x)^4 = cos(x)^4 - cos(x)^2:
cos(x)^4 - cos(x)^2 = ^?cos(x)^4 - cos(x)^2
The left hand side and right hand side are identical:
Answer: (identity has been verified)
Answer:
10°
Step-by-step explanation:
According remote interior angles, 4k + 5 + 6k + 10 = 115.
10k + 15 = 115
10k = 100
k = 10
Hope this helps :)
Have a nice day!
Answer:
16 in × 20 in
Step-by-step explanation:
- Finding the % of the picture that can fit in 16×20 frame
Area of picture= length by width
=4*6=24 in²
Area of frame=Length by width
=16*20=320 in²
% of the picture in the frame will be
(24/320) * 100% =7.5%
2. Finding the % of the picture that can fit in 18 × 24 frame
Area of picture=24 in²
Area of frame =Length by width
=18*24=432 in²
% of the picture in the frame will be;
(24/432)*100%=5.6%
The frame 16 by 20 in will keep 7.5% of the original picture
The frame 18 by 24 in will keep 5.6% of the original picture
Hence you should use the frame of 16 by 20 in because it will keep more of the original picture.
