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Step2247 [10]
3 years ago
7

The hypotenuse of a 45°-45°-90° triangle measures 10 StartRoot 5 EndRoot in. A right triangle is shown. The hypotenuse has a len

gth of 10 StartRoot 5 EndRoot and the lengths of the other 2 sides are congruent. What is the length of one leg of the triangle? 5 StartRoot 5 EndRoot 5 StartRoot 10 EndRoot 10 StartRoot 5 EndRoot 10 StartRoot 10 EndRoot
Mathematics
2 answers:
Reptile [31]3 years ago
6 0

Answer:

if thats not part of your answer guys here i got you

12 StartRoot 2 EndRoot in.  meaning <u><em>B </em></u>

if u have the number with 24

Step-by-step explanation:

egd 2020

this is my question the hypotenuse of a 45°-45°-90° triangle measures 24 inches. What is the length of the one leg of the triangle?

the answer was <u>B</u>

suter [353]3 years ago
4 0

Answer:

5\sqrt{10}\ units

5 StartRoot 10 EndRoot

Step-by-step explanation:

we know that

The legs of a 45°-45°-90° triangle are congruent

Let

x ---->  the length of one leg of the triangle

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the hypotenuse

a and b are the legs

we have

c=10\sqrt{5}\ units

a=b=x\ units

substitute

(10\sqrt{5})^2=x^2+x^2

500=2x^2\\x^2=250\\x=\sqrt{250}\ units

Simplify

x=5\sqrt{10}\ units

5 StartRoot 10 EndRoot

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3 years ago
5x-4y=-18 what is the three point on a graph for this equation
Tju [1.3M]
(1)Draw the "y" line . It goes up and down. 
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<span>Start at -20 and go to 10 </span>
<span>(2)Draw the "x" line. it goes side to side. </span>
<span>place the x line at the zero point of the y line. I'm sure you will see your paper looks like the letter "t". Perfectly at a right angle. you could use the corner of a book to square it. </span>

<span>Now for the maths 5x - 4y = -18. The most important symbol here is the "=" sign. </span>
<span>(3) rearrange the equation so that y is on one side of "=" and x is on the other side. </span>
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5 0
3 years ago
(1 - cos ß)(1 + cos ß) =1/cosec^2(ß)
iVinArrow [24]

Step-by-step explanation:

L.H.S=(1-cosB)(1+cosB)

=(1-cos^2B). {using (a+b) (a-b)=(a^2-b^2)in second step}

=sin^2B

=1/cosec^2B

Therefore,L.H.S=R.H.S proved

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2 years ago
Convert to slope intercept form.<br><br> y + 6 = 4/5 (x + 3)
xenn [34]
X = 5y + 30/4 - 3 is the answer.
7 0
3 years ago
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Drag each set of column entries to the correct location in the matrix equation. Not all sets of entries will be used. A biker ne
ANEK [815]

Answer:

The matrix equation is \left[\begin{array}{ccc}1&1&1\\1&-1/2&0\\0&2&-1\end{array}\right]=\left[\begin{array}{c}120&35&20\end{array}\right]

Step-by-step explanation:

* Lets change the story problem to equations

- The distance between the starting point and checkpoint 1 is x

- The distance between checkpoint 1 to checkpoint 2 is y

- The distance between checkpoint and the finish line is z

- The total distance for the race is 120 miles

∴ x + y + z = 120 ⇒ (1)

-The distance from the starting point to checkpoint 1 is 35 miles

 more than half the distance from checkpoint 1 to checkpoint 2

∵ The distance from the starting point to checkpoint 1 is x

∵ The distance from checkpoint 1 to checkpoint 2 is y

- x is more than half y by 35

∴ x = 35 + (1/2) y ⇒ subtract (1/2) y from both sides

∴ x - (1/2) y = 35 ⇒ (2)

- The distance from checkpoint 2 to the finish line is 20 miles less

 than twice the distance from checkpoint 1 to checkpoint 2

∵ The distance from checkpoint 2 to the finish line is z

∵ the distance from checkpoint 1 to checkpoint 2 is y

- z is less than twice y by 20

∴ z = 2y - 20 ⇒ add 20 to both sides

∴ z + 20 = 2y ⇒ subtract z from both sides

∴ 2y - z = 20 ⇒ (3)

* Now lets write the three equations

# x + y + z = 120 ⇒ (1)

# x - (1/2) y = 35 ⇒ (2)

# 2y - z = 20 ⇒ (3)

- Now lets write the matrix equation that models this situation

∴ \left[\begin{array}{ccc}1&1&1\\1&-1/2&0\\0&2&-1\end{array}\right]=\left[\begin{array}{c}120&35&20\end{array}\right]

6 0
3 years ago
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