16r^2+ 2r -4r
16r^2 - 2r
2r ( 8r -1)
Answer:
y = -2x - 5
Step-by-step explanation:
<u>1) Find the slope of the line.</u>
The slope of the original line is the same as the slope of the parallel line.
Slope formula:
![m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_%7B2%7D%20-%20y_%7B1%7D%7D%7Bx_%7B2%7D%20-%20x_%7B1%7D%7D)
In this case you can choose any 2 set of points on the table.
=
=
= -2
So the slope of the line is -2
<u>2) Use the point-slope formula to find the equation of the line.</u>
Point-slope formula:
![y - y_{1} = m(x - x_{1})](https://tex.z-dn.net/?f=y%20-%20y_%7B1%7D%20%20%3D%20m%28x%20-%20x_%7B1%7D%29)
Now plug in the point (0, -5) and the slope -2 into the equation.
y - (-5) = -2(x - 0)
y + 5 = -2(x - 0)
To solve the equation first apply the distributive property.
y + 5 = -2x + 0
y + 5 = -2x
Next, subtract 5 from sides.
y = -2x - 5
You know have your equation in point-slope form!
Answer:
8/3 or 2 and 2/3
Step-by-step explanation:
Answer:
128
Step-by-step explanation:
32 x 4 = 128
o
32 + 32 + 32 + 32 = 128