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4 years ago

Five less than four times a number is 19

Mathematics

1 answer:

Ludmilka [50]4 years ago

8 0

I think that it is 6. Hope it helps.
6 × 4 = 24
24 - 5 = 19

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One of the cars are blue it van travel 31 1/2 miles on 1 1/4 gallons of gasoline .Another car is red it can travel 28 4/5 miles

yuradex [85]

Answer:

Step-by-step explanation:

One of the cars are blue. it can travel 31 1/2 miles on 1 1/4 gallons of gasoline. Converting 31 1/2 miles to decimal, it becomes 31.5 miles. Converting 1 1/4 gallons of gasoline to decimal, it becomes 1.25 gallons of gasoline.

Therefore, the miles per gallon for the blue car is

31.5/1.25 = 25.2 miles per gallon.

Another car is red it can travel 28 4/5 miles on 4/5 gallon of gasoline.

Converting 28 4/5 miles to decimal, it becomes 28.8 miles. Converting 4/5 gallons of gasoline to decimal, it becomes 0.8 gallons of gasoline.

Therefore, the miles per gallon for the red car is

28.8/0.8 = 36 miles per gallon.

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3 years ago

What 12+9 <br> A 99 <br> B 4<br> C 0

chubhunter [2.5K]

Answer:

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3 years ago

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per

ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that $\mu = 2$

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

We want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353$

$P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707$

$P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707$

$P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804$

$P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902$

$P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176$

1.76% probability that in one hour more than 5 clients arrive

8 0

3 years ago

Read 2 more answers

Someone help i’m taking a test!

Ulleksa [173]

Answer:

the answer is d

Step-by-step explanation:

The graph is increasing by a distance of 35 each hour, showing that the bear is running 35 mph

hope this helps, have a wonderful day :))

5 0

3 years ago

24. In order to make the playoffa soccer team must get 20 points during the regular season. The team gets 2

stira [4]

Answer:10×12????=120 i think thats what your aski,

Step-by-step explanation:

7 0

3 years ago