Do you want this explained ? or the answer
Answer:
Zeros: 5, multiplicity 1; -4 multiplicity 2; degree 3
y=1(x-5)^1(x+4)^2
y=(x+4)^2(x-5)
y=(x^2+8x+16)(x-5)
y=x^3+8x^2+16x-5x^2-40x-85
y=x^3+3x^2-24x-85
Step-by-step explanation:
2πr^{2} + 2πrh =SA
2π1.5x^{2} + 2π1.5 x 24
2π2.25 + 2π36
4.5π + 72π
SA\approx= 240.3 SQ in
hope this helps
