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lbvjy [14]
3 years ago
12

A store purchases televisions from a factory for $\$$87.89 each. The store normally sells one of these televisions for 225$\%$ o

f the factory cost, but a store coupon gives 25$\%$ off this selling price. Ignoring tax, how much does a customer with this coupon pay for the television?
Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0

Answer:The amount that a customer with this coupon will pay is $148.3245

Step-by-step explanation:

The price at which the store purchases televisions from a factory is for $87.89 each. The store normally sells one of these televisions for 225% of the factory cost. This means that the price at which each television is sold at the store is

225/100 × 87.89 = $197.7525

The store coupon gives 25% off this selling price. The value of the coupon would be

25/100 × 197.7525 = $49.428

The amount that a customer with this coupon will pay for the television would be

197.7525 - 49.428 = $148.3245

Agata [3.3K]3 years ago
3 0

Answer:

168.75 is the answer most probably

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\bf (x-4)^2+(y+1)^2\qquad (3,6)~~ \begin{cases} x = 3\\ y = 6 \end{cases}\implies (3-4)^2+(6+1)^2 \\\\\\ (-1)^2+7^2\implies 1+49\implies 50

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Evaluate 2(x+ 1 - 3 when x = 6 O Ο Α. 11 OB. 5 O C. 8 ( D. 10
Mashutka [201]

\implies {\blue {\boxed {\boxed {\purple {\sf {A. \:11}}}}}}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

2 \: ( \: x + 1 \: ) - 3

Plugging in the value "x\:=\:6" in the above expression, we have

= 2 \: ( \: 6 + 1 \: ) - 3

= 2 \: ( \: 7 \: ) - 3

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= 11

<h3><u>Note</u>:-</h3>

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\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

5 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
saul85 [17]

Answer:

Option B is the correct answer

Step-by-step explanation:

<u>A line segment is a line drawn with two end points.</u>

1.) Option A is a point

2.) <u>Option B is a line segment</u>

3.) Option C is a ray

4.) Option D is a line

Hope this helps!

8 0
2 years ago
Please solve with explanation
leva [86]

Answer:

i pray you get it right lol

Step-by-step explanation:

just ask a teacher

8 0
2 years ago
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
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