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3 years ago

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A student determined that the area of shown above is A= 137.71ft² . the students work is shown below. Evaluate the students answ

er

1 answer:

MArishka [77]3 years ago

6 0

Where is the students work?

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I NEED HELP ASAP:

olga55 [171]

First, you have to do some factorization

60 = {1,2,3,4,5,6,10,12,15,20,30,60}
72 = {1,2,3,4,6,8,9,12,18,24,36,72}

the GCF is 12

now we find the number that you multiply by 12 to get 60 and another number to get 72.

12 x 5 = 60
12 x 6 = 72

now we notice if you add 60 + 72, we can now tell that it also equals (12)(5)+(12)(6)= 12(5+6)

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4 years ago

PLEASE HELP!!<br> Factor <br> 6x^2-42x-54<br><br> Please show work!

skad [1K]

first, rewrite 54 as 6•9

next, rewrite 42 as 6•7

then, that gets you 6x^2 -6•7x- 6•9

lastly, factor out the common term (6)

and then you get 6(x^2-7x-9)

<u>please mark as brainliet <3</u>

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3 years ago

If the length of line segment AB is 9 inches, the total number of point 4 inches from Point A and 6 inches from Point B is

brilliants [131]

9514 1404 393

Answer:

B. Two

Step-by-step explanation:

There are two points that are 4 inches from A and 6 inches from B.

__

<em>Additional comment</em>

They are at the intersection points of circle A with radius 4 inches and circle B with radius 6 inches.

4 0

2 years ago

Find the coordinates of the intersection of the diagonals of parallelogram GHJK with vertices G(0,2), H(4,2), J(3,0), and K(-1,0

zimovet [89]

Answer:

(1.5,1)

Step-by-step explanation:

The midpoint of G and H is at (2,2).

The midpoint if J and K is (1,0)

The midpoint of the two midpoints is (1.5,1)

You could also i.e. directly ask for the midpoint of H an K, OR, G and J, and you would get the same final result.

8 0

3 years ago

Farmer Ed has 9,500 meters of fencing,

Andreas93 [3]

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for x</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equation</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distribute</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = </em><em>- </em><em>b</em><em>/2a = -7500/[2(-2)] = 1875</em>

<em>/2a = -7500/[2(-2)] = 1875 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2 </em>

5 0

3 years ago