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2 years ago

12

A student determined that the area of shown above is A= 137.71ft² . the students work is shown below. Evaluate the students answ

er

1 answer:

MArishka [77]2 years ago

6 0

Where is the students work?

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I need help with this please

Kazeer [188]

Answer:

score = 63

Step-by-step explanation:

1. To write the proportion take the score of the test over the number of points and set it equal to the percent over 100

score 90

----------- = -----------

70 100

Using cross products

100 * score = 90*70

100 score = 6300

Divide by 100

100/100 * score = 6300/100

score = 63

8 0

2 years ago

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

What is 618,334 rounded to the nearest 10,000

weqwewe [10]

The answer would be 620000

4 0

3 years ago

Read 2 more answers

As the weight held by a spring increases, the length of the spring increases, proportionally. Suppose a 2-lb weight stretches a

meriva

The aswer would be B because you have to divide a couple numbers to get 20in.

6 0

3 years ago

Ben is 12 years older than Ishaan. Ben and Ishaan first met two years ago. Three years ago, Ben was 4 times as old as Ishaan. Ho

Stels [109]

Answer:

Ben is 19 Ishaan is 7

Step-by-step explanation:

7 0

3 years ago