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9966 [12]
3 years ago
10

Myas bed room is into shape of a rectangle Euler prism 15 feet long 12 feet wide and 10 feet high it has no windows Mier wants t

o pay all four walls including the door in the ceiling what is surface area will she paint
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
6 0

Answer:

15x12x10.

The roof is 12x15.

Two walls are each 12x10.

The other two walls are each 15x10.

12x15 + 12x10 + 15x10 = 180 + 120 + 150 = 450 ft^2

Step-by-step explanation:

You might be interested in
When the Bucks play Chiefs at football, the probability that the Chiefs, on present form, will win is 0.56. In a competition, th
Tom [10]

Answer:

The probability that Swallows will win the trophy is 0.8064

The probability that Rucks will win the trophy is 0.1936

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the Swallows win, or they do not. The probability of them winning a game is independent of any other game, which means that the binomial probability distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability the Swallows wins is 0.56

This means that p = 0.56

2 games:

This means that n = 2

The probability that Swallows will win the trophy is

Probability they win at least one game, so:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.56)^{0}.(0.44)^{2} = 0.1936

Then

P(X \geq 1) = 1 - 0.1936 = 0.8064

0.8064 = 80.64% probability the Swallows win the trophy and 0.1936 probability that the Rucks win the trophy.

5 0
3 years ago
Use the four-step process to find f'(x) and then find f'(1), f'(2), and f'(3).
Soloha48 [4]

Step 1: evaluate f(x+h) and f(x)

We have

f(x+h) = -(x+h)^2+6(x+h)-5 = -(x^2+2xh+h^2)+6x+6h-5

= -x^2-2xh-h^2+6x+6h-5

And, of course,

f(x)=-x^2+6x-5

Step 2: evaluate f(x+h)-f(x)

f(x+h)-f(x)=-x^2-2xh-h^2+6x+6h-5-(-x^2+6x-5)=-2xh-h^2+6h

Step 3: evaluate (f(x+h)-f(x))/h

\dfrac{f(x+h)-f(x)}{h}=-2x-h+6

Step 4: evaluate the limit of step 3 as h->0

f'(x) = \displaystyle \lim_{h\to 0} \dfrac{f(x+h)-f(x)}{h}=-2x+6

So, we have

f'(1) = -2\cdot 1+6 = 4,\quad f'(2) = -2\cdot 2+6 = 2,\quad f'(3) = -2\cdot 3+6 = 0

5 0
3 years ago
I’ve posted this so many times someone finish this so I can sleep and not wake up to another assignment
arsen [322]
Hi! I’m not done with it yet, but I just wanted to let you know that I’m working on this for you! Please try not to stress!
3 0
3 years ago
Is 10/15 equivalent?
ss7ja [257]
You can divide both the top by 5
10/5 = 2
15/5 = 3

Therefore 10/15 is equivalent to 2/3
3 0
3 years ago
Read 2 more answers
The following tables each show the inventory of a warehouse and the number of orders for four different products which have been
snow_lady [41]
Orders: x
Inventory: y

1) First table
x2-x1=6-3→x2-x1=3
y2-y1=1920-1960→y2-y1=-40

x3-x2=9-6→x3-x2=3=x2-x1
y3-y2=1900-1920→y3-y2=-20 different to y2-y1=-40. The table does not represent a linear relationship.

2) Second table
x2-x1=7-5→x2-x1=2
y2-y1=1860-1900→y2-y1=-40

x3-x2=9-7→x3-x2=2=x2-x1
y3-y2=1820-1860→y3-y2=-40=y2-y1

x4-x3=11-9→x4-x3=2=x3-x2
y4-y3=1780-1820→y4-y3=-40=y3-y2

x5-x4=13-11→x5-x4=2=x4-x3
y5-y4=1740-1780→y5-y4=-40=y4-y3

The table represents a linear relationship.

3) Third table
x2-x1=2-1→x2-x1=1
y2-y1=1000-2000→y2-y1=-1000

x3-x2=3-2→x3-x2=1=x2-x1
y3-y2=500-1000→y3-y2=-500 different to y2-y1=-1000. The table does not represent a linear relationship.

4) Fourth table
x2-x1=6-4→x2-x1=2
y2-y1=1640-1840→y2-y1=-200

x3-x2=8-6→x3-x2=2=x2-x1
y3-y2=1360-1640→y3-y2=-280 different to y2-y1=-200. The table does not represent a linear relationship.

Answer: The second <span>table best represents a linear relationship.</span>
8 0
4 years ago
Read 2 more answers
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