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2 years ago

Write each parabola in the form y-k=a(x-h)^2 aand determine its vertex.

Mathematics

2 answers:

mezya [45]2 years ago

6 0

Answer:

Step-by-step explanation:

$y=-x^2-4x-1\\=-(x^2+4x+4)+4-1\\=-(x+2)^2+3\\\\Vertex=(-2;3)\\\\$

$y+x^2+2=0\\y=-x^2-2\\\\y=-(x-0)^2-2\\Vertex=(0;-2)\\$

Viefleur [7K]2 years ago

5 0

Answer:

Step-by-step explanation:

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What is the value of n? enter your answer in the box.

ankoles [38]

Answer:

n = 8

Step-by-step explanation:

The product of the parts of one chord is equal to the product of the parts of the other chord, that is

3n = 4 × 6 = 24 ( divide both sides by 3 )

n = 8

4 0

3 years ago

on a recent hike through riverbend park antoinette traveled 2/3 mile in 1/3 hour . Which unit rate describes antoinettes speed i

My name is Ann [436]

Answer:

Her speed is of 2 miles per hour.

Step-by-step explanation:

Velocity:

The velocity is given by the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance and t is the time.

2/3 mile in 1/3 hour .

This means that $d = \frac{2}{3}, t = \frac{1}{3}$

Which unit rate describes antoinettes speed in miles per hour?

This is v. So

$v = \frac{d}{t} = \frac{\frac{2}{3}}{\frac{1}{3}} = \frac{2}{3}*\frac{3}{1} = 2$

Her speed is of 2 miles per hour.

5 0

3 years ago

Martha filled a bowl with 0.5 cup of flour and 0.75 cup of milk. To the nearest cup, how many cups of ingredients were in the bo

Damm [24]

0.5 + 0.75 = 1.25

1.25 rounds off to 1.

7 0

3 years ago

The difference between <img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7B72%7D%20%20" id="TexFormula1" title=" \sqrt[2]{72}

ollegr [7]

$\sqrt{72}-\sqrt{8}=\sqrt{36\cdot 2}-\sqrt{4\cdot 2}\\\\=6\sqrt{2}-2\sqrt{2}=4\sqrt{2}$

4 0

3 years ago

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

$(a^m)^n = a^{m\times n}$

$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

5 0

2 years ago

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