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3 years ago

Is the following relation a function?

Mathematics

2 answers:

Leto [7]3 years ago

8 0

no it is not one x cannot have 2 y's.

Reika [66]3 years ago

3 0

No it is not a function. For this kind of diagram, if there are 2 arrows going to the same number on the right, it is not a function.
I hope this helps love! :)

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Laws Of Indicies<br>Can someone please help me with this?

nasty-shy [4]

Answer:

See below

Step-by-step explanation:

$1) : {a}^{5} {b}^{4} {c}^{3} \div {a}^{2} {b}^{3} c \\ \\ = {a}^{5 - 2} {b}^{4 - 3} {c}^{3 - 1} \\ \\ = {a}^{3} {b}^{1} {c}^{2} \\ \\ = {a}^{3} {b} {c}^{2} \\ \\ \\2)\: (x^2 y^3)^3\\\\= x^{2\times 3}y^{3\times 3}\\\|= x^{6}y^{9}\\\\\\3)\:5 {a}^{4} \div ( {a}^{2} \times 3a) \\ \\ = 5 {a}^{4} \div (3 {a}^{2 + 1} ) \\ \\ = 5 {a}^{4} \div (3 {a}^{3} ) \\ \\ = \frac{5}{3} {a}^{4 - 3} \\ \\ = \frac{5}{3} {a} \\ \\ \\ 4)\: \frac{14 {a}^{5} }{2 {a}^{3} \times 7 {a}^{4} } \\ \\ = \frac{14 {a}^{5} }{2 \times 7 {a}^{3 + 4} } \\ \\ = \frac{ \cancel{14} {a}^{5} }{ \cancel{14}{a}^{3 + 4} } \\ \\ = \frac{ {a}^{5} }{ {a}^{7} } \\ \\ = {a}^{5 - 7} \\ \\ = {a}^{ - 2} \\ \\ = \frac{1}{{a}^{2} } \\ \\$

8 0

3 years ago

Read 2 more answers

Please help me out and with work included

irina1246 [14]

Hope that makes sense

3 0

3 years ago

Solve the quadratic inequality

RUDIKE [14]

Answer:

C: x > 4

none of the others

4 0

3 years ago

Help ASAP!!! Please show all work!!!!!!!

Anastaziya [24]

Answer:

x = 2 and x = -3

Step-by-step explanation:

We need to find the value of x in the below expression.

$\sqrt{x+7} -1=x$

Adding 1 to both sides,

$\sqrt{x+7} -1+1=x+1\\\\\sqrt{x+7}=x+1$

Squaring both sides,

$x+7=(x+1)^2\\\\x+7=x^2+1+2x\\\\x^2+1+2x-x-7=0\\\\x^2+x-6=0\\\\x=2\ and\ -3$

Hence, this is the required solution.

6 0

3 years ago

Read 2 more answers

The graph shows the functions f(x), p(x), and g(x):

Sidana [21]

The function f(x) is:

f(x)=x

This is because the line f(x) passes through the points (-1,-1), (0,0), (1,1) etc.

The function p(x) is:

p(x)=mx+C

Whereby (m) is the slope and (C) is a constant.

m=-4/3, as m=tan(ω)=O/A=-4/3 as slope is negative.

Now when y=-3, x=-3.

So:

-3=-4/3 *(-3) +C

-3= 4 + C

C=-7

This means that:

p(x)=-4/3x -7

Now, where p(x)=g(x), x=-6.

p(-6)=-4/3 * (-6) -7

p(-6)=24/3 -7

p(-6)=8-7

p(-6)=1

Therefore:

p(x) and g(x) meet at (-6, 1) and the solution to p(x)=g(x) is x=-6.

3 0

3 years ago