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KATRIN_1 [288]
4 years ago
9

Which is an example of the associative property?

Mathematics
2 answers:
emmasim [6.3K]4 years ago
6 0
I say letter c i think for sure
Mrac [35]4 years ago
5 0
I believe that the answer is C.
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you deposit $7,900 in a money-market account that pays an annual interest rate of 4.3%. the interest is compounded quarterly. ho
Sladkaya [172]
<span><span>anonymous </span> 3 years ago</span>we are solving for A, A is the future amount A=? P is the present value, so we were told 7,900, so p=7900 r is the interest rate, so 4.3%, but in decimal form so r=0.043 k is the how often it is 'compounded', it says quarterly, so k=4 n is how long, 3 years, so n=3 <span>A=P(1+<span>rk</span><span>)<span>n∗k</span></span></span> plug in the values
<span>A=8981.51</span>
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3 years ago
How many real numbers solutions are there in the equation?<br> 0=-3x^2+x-4?
Kisachek [45]
There is only 1 solution

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3 years ago
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Deffense [45]
16 is going to be right
8 0
3 years ago
Read 2 more answers
Jason is mikes older brother. the sum of their ages is 25. the differnece in their ages is 7 write the system of equation that r
Jet001 [13]

Answer:

Equation 1: m+j=25

Equation 2: j=m+5


I hope this helps! Good luck! <3


-YAND3R3


5 0
3 years ago
A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard
bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44

In point a)  

\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}

  = \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2

value= (1- \frac{1}{k^2}) \times 100 \% =75\%

In point b)

\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma  \\\\= |(x-\mu)|\leq 2.5 \times 4.44  \\\\  = |(x-\mu)|\leq 1.11 \\\\ =  (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)

In point c)

\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\

In point d)

using standard normal variate

x=20.17\\\\  z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17

8 0
3 years ago
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