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bearhunter [10]
3 years ago
12

Check all that apply. x2 + 4x - 9 = 5x + 3

Mathematics
1 answer:
kakasveta [241]3 years ago
8 0

Answer:

The solution set is (-3, 4).

Step-by-step explanation:

x2 + 4x - 9 = 5x + 3

x^2 + 4x - 5x - 9 - 3 = 0

x^2 -x - 12 = 0

(x - 4)(x + 3) = 0

x = -3, 4.

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You would do ten times fifty. which would be 500
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3 years ago
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What is the value of x? tangent lines acellus
liberstina [14]

Answer:

30°

Step-by-step explanation:

the three interior angles of a triangle add up to 180, so 60° + 90°+ 30° just works. Sorry it's such a bad explanation, but the answer works . I have acellus too and I entered the answer before answering your question.

5 0
3 years ago
5 watermelons 6 cantaloupes cost $54. 4 watermelons and 8 cantaloupes $56. how much is a cantaloupe
GREYUIT [131]

Answer:

A cantaloupe costs $4

Step-by-step explanation:

Watermelons = W

Cantaloupes = C

Write given statements as equations

5W + 6C = 54

4W + 8C = 56

Simplify the second equation

4W + 8C = 56

Subtract 8C from both sides of the equation

4W = 56 - 8C

Divide both sides of the equation by 4

W = 14 - 2C

Substitute into second equation

5W + 6C = 54

5(14 - 2C) + 6C = 54

Multiply 5(14 - 2C)

70 - 10C + 6C = 54

Add -10C + 6C

70 - 4C = 54

Add 4C to both sides of the equation

70 = 54 + 4C

Subtract 54 from both sides of the equation

16 = 4C

Divide both sides of the equation by 4

C = 4

A cantaloupe costs $4

5W + 6(4) = 54

Multiply 6(4)

5W + 24 = 54

Subtract 24 from both sides of the equation

5W = 30

Divide both sides of the equation by 5

W = 6

A cantaloupe costs $4

A watermelon costs $6

Hope this helps :)

8 0
3 years ago
7TH GRADE MATH!!! PLZ HELP WILL MAKE BRAINLIEST AND THANKS!
ivanzaharov [21]

Answer: A, C, D

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:)

3 0
3 years ago
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively. Pl
kicyunya [14]
Hello,

u_{0} =a\\
 u_{1} =a*r\\
 u_{2} =a*r^{2}=-6\\
 u_{3} =a*r^{3}\\
 u_{4} =a*r^{4}\\
 u_{5} =a*r^{5}=162\\
....\\
\boxed{ u_{n} =a*r^{n}} \\

\dfrac{ 162}{-6} = \dfrac{ u_{5} }{ u_{3}} = \dfrac{ a*r^{5}}{ a*r^{2}} =r^3= -27\\
==\ \textgreater \  r=-3\\

 u_{2} =a*r^{2}=-6=a*(-3)^2 \ ==\ \textgreater \  a=-\frac{6}{9} =-\frac{2}{3}\\


\boxed{ u_{n} =-\frac{2}{3}*(-3)^{n}=(-1)^{n+1}*2*3^{n-1}} \\


8 0
3 years ago
Read 2 more answers
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