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CaHeK987 [17]
3 years ago
16

What is the common ratio for the sequence 5, -10, 20, -40, ...?

Mathematics
2 answers:
Lesechka [4]3 years ago
7 0
The common ratio would be -2
-10/5 = -2
-40/20 = -2
solmaris [256]3 years ago
4 0
The sequence is multiply by -2
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A 40 oz jar of peanut butter costs 5.25. how much does a 100 oz jar cost
Karolina [17]

Answer:

13.13

Step-by-step explanation:

5.25 x 100/40 is 13.125 which rounds up to 13.13

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Find The Perimeter Of The Shaded Region <br><br> 90 ft<br> 58 ft<br> 24 ft <br> 38 ft
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L  = 14 - 6 = 8
w = 15 - 4 = 11

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answer
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6. Camille is a first year accountant and a recent college graduate. She is paid a salary
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jk ima awnser in one sec

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Find and compare the growth rates in the weekly number of specialty items produced at each factory.
DerKrebs [107]

0.129 is the change in the growth rate of company.

According to statement

we have to find and compare the growth rate of the company weekly.

we use the growth rate formula is

GROWTH RATE = present - past / present

Substitute the values in this formula

1st week = 220-190 / 220

1st week = 0.136

2nd week = 252-220 / 252

2nd week = 32 / 252

2nd week = 0.126

3rd week = 290-252 / 290

3rd week = 0.131

4th week = 337 - 290 / 337

4th week = 0.139

5th week = 380 - 337 / 380

5th week = 0.113

6th week = 440 - 380 / 440

6th week = 0.136

7th week = 505 - 440 / 505

7th week = 0.128

Now we find the average value of growth rate

Average = 0.136 + 0.126+0.131+0.139+0.113+0.136+0.128 /7

Average = 0.909/7

Average = 0.129

So, 0.129 is the change in the growth rate of company.

Learn more about GROWTH RATE here brainly.com/question/20115298

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7 0
2 years ago
Physics! Someone help me! Its due today please!
icang [17]

Step-by-step explanation:

We have,

Mass of ball is 9 kg

Initial speed, u = 5 m/s

Final speed, v = -2 m/s (negative as it bounces off)

(a) The change in velocity of the bowling ball is :

\Delta v=v-u\\\\\Delta v=-2-5\\\\\Delta v=-7\ m/s

(b) Change of momentum of the ball is :

p=m\Delta v\\\\p=90\times (-7)\\\\p=-630\ kg-m/s

|p| = 630 kg-m/s

(c) Impulse momentum theorem states that the change in momentum of the ball is equal to the impulse exerted on the ball. So, impulse is 630 kg-m/s.

(d) Impulse is also given by :

J=F\times t\\\\F=\dfrac{J}{t}\\\\F=\dfrac{630}{0.3}\\\\F=2100\ N

6 0
3 years ago
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