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CaHeK987 [17]
4 years ago
16

What is the common ratio for the sequence 5, -10, 20, -40, ...?

Mathematics
2 answers:
Lesechka [4]4 years ago
7 0
The common ratio would be -2
-10/5 = -2
-40/20 = -2
solmaris [256]4 years ago
4 0
The sequence is multiply by -2
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1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
3 years ago
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Answer:

y = (x-16)/7

Step-by-step explanation:

x - 7y = 16

~Subtract x to both sides

-7y = 16 - x

~Divide -7 to everything

y = (16-x)/7

Best of Luck!

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3 years ago
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FromTheMoon [43]

Answer:

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6 0
3 years ago
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Answer:

(- 1, 2)

Step-by-step explanation:

Given a quadratic in standard form y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

f(x) = x² + 2x + 3 ← is in standard form

with a = 1 and b = 2, hence

x_{vertex} = - \frac{2}{2} = - 1

Substitute x = - 1 into f(x) for corresponding value of y

f(- 1) = (- 1)² + 2(- 1) + 3 = 1 - 2 + 3 = 2

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4 0
3 years ago
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