All categories

4 years ago

I only need a number value

Mathematics

1 answer:

lorasvet [3.4K]4 years ago

5 0

Answer:

50°

Step-by-step explanation:

There you go.......

You might be interested in

The point ( -6 , 8 ) is reflected across the y axis. What is the coordinates of the reflection

Digiron [165]

The new coordinations would be (6,8)

6 0

3 years ago

Read 2 more answers

A large beach ball has a diameter of 4.14 feet. How much air can fill the ball?

aalyn [17]

The beach ball can hold 37.15 cubic feet of air

Solution:

Given that the beach ball has a diameter of 4.14 feet

We are asked to find how much air can fill the ball. This means that we have to find the volume of the ball

Finding volume of ball:

Given diameter = 4.14 feet

We know that radius is half of diameter

$radius = \frac{diameter}{2}$

$radius = \frac{4.14}{2} = 2.07$

Since ball is a sphere, Volume of sphere is given as:

$volume of sphere = \frac{4 \pi r^3}{3}$

By substituting the value of radius we get,

$v = \frac{4 \pi \times 2.07^3}{3}\\\\v = \frac{4 \times 3.14 \times 8.869743}{3}\\\\v = 37.15$

Hence the beach ball can hold 37.15 cubic feet of air

6 0

4 years ago

Y=x.arctan(x)^1/2. find dy/dx. pls show steps

Whitepunk [10]

$y=x(\arctan x)^{1/2}$

Use the product rule first:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}$

Use the chain rule to compute the derivative of $(\arctan x)^{1/2}$ . Let $z=(\arctan x)^{1/2}$ and take $u=\arctan x$ , so that by the chain rule

$\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}$

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}$

$\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}$

So we have

$\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}$

You can rewrite this a bit by factoring $(\arctan x)^{-1/2}$ , just to make it look neater:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)$

3 0

3 years ago

Which is an equation?

ziro4ka [17]

An equation must contain an equals sign. That means answer A is the only one that is an equation.

Hope this helps!!

5 0

4 years ago

Read 2 more answers

Plz help meh out on my math hw

Elodia [21]

Hello!

Let's write this as a system of equations.

L=3w

wL=432

Let's plug in our value for L into the second equation, and solve for w.

w(3w)=432

3w²=432

w²=144

w=12

Now, let's plug our w value into the first equation.

L=3(12)

L=36

Therefore, the length is 36 and the width is 12.

I hope this helps!

5 0

3 years ago