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marishachu [46]
4 years ago
12

I only need a number value

Mathematics
1 answer:
lorasvet [3.4K]4 years ago
5 0

Answer:

50°

Step-by-step explanation:

There you go.......

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The point ( -6 , 8 ) is reflected across the y axis. What is the coordinates of the reflection
Digiron [165]

The new coordinations would be (6,8)

6 0
3 years ago
Read 2 more answers
A large beach ball has a diameter of 4.14 feet. How much air can fill the ball?
aalyn [17]

The beach ball can hold 37.15 cubic feet of air

<u>Solution:</u>

Given that the beach ball has a diameter of 4.14 feet

We are asked to find how much air can fill the ball. This means that we have to find the volume of the ball

<em><u>Finding volume of ball:</u></em>

Given diameter = 4.14 feet

We know that radius is half of diameter

radius = \frac{diameter}{2}

radius = \frac{4.14}{2} = 2.07

Since ball is a sphere, Volume of sphere is given as:

volume of sphere = \frac{4 \pi r^3}{3}

By substituting the value of radius we get,

v = \frac{4 \pi \times 2.07^3}{3}\\\\v = \frac{4 \times 3.14 \times 8.869743}{3}\\\\v = 37.15

Hence the beach ball can hold 37.15 cubic feet of air

6 0
4 years ago
Y=x.arctan(x)^1/2. find dy/dx. pls show steps​
Whitepunk [10]

y=x(\arctan x)^{1/2}

Use the product rule first:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dx}{\mathrm dx}(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}

\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+x\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}

Use the chain rule to compute the derivative of (\arctan x)^{1/2}. Let z=(\arctan x)^{1/2} and take u=\arctan x, so that by the chain rule

\dfrac{\mathrm dz}{\mathrm dx}=\dfrac{\mathrm dz}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm dz}{\mathrm du}=\dfrac{\mathrm du^{1/2}}{\mathrm du}=\dfrac12u^{-1/2}

\dfrac{\mathrm du}{\mathrm dx}=\dfrac{\mathrm d\arctan x}{\mathrm dx}=\dfrac1{1+x^2}

\implies\dfrac{\mathrm d(\arctan x)^{1/2}}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}(1+x^2)}

So we have

\dfrac{\mathrm dy}{\mathrm dx}=(\arctan x)^{1/2}+\dfrac x{2(\arctan x)^{1/2}(1+x^2)}

You can rewrite this a bit by factoring (\arctan x)^{-1/2}, just to make it look neater:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac1{2(\arctan x)^{1/2}}\left(2\arctan x+\dfrac x{1+x^2}\right)

3 0
3 years ago
Which is an equation?
ziro4ka [17]
An equation must contain an equals sign. That means answer A is the only one that is an equation.

Hope this helps!!
5 0
4 years ago
Read 2 more answers
Plz help meh out on my math hw
Elodia [21]

Hello!

Let's write this as a system of equations.

L=3w

wL=432

Let's plug in our value for L into the second equation, and solve for w.

w(3w)=432

3w²=432

w²=144

w=12

Now, let's plug our w value into the first equation.

L=3(12)

L=36

Therefore, the length is 36 and the width is 12.

I hope this helps!


5 0
3 years ago
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