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Katarina [22]
4 years ago
9

Find 4ab when (a+b)=15 and (a-b)=12

Mathematics
2 answers:
aev [14]4 years ago
5 0

Answer:

81

Step-by-step explanation:

here,

(a+b)=15 -------(1)

(a-b)=12 -------(2)

Equating the equation (1) and (2)

a + b = 15

a - b = 12

(b gets cancelled having opposite signs)

or, 2a = 27

or, a = 27÷2

a = 13.5

then, putting value of a in equation (1)

a+b=15

or, 13.5 + b=15

or, b=15-13.5

b=1.5

lastly,

4ab = 4×13.5×1.5

= 81

hope it helps!!

Volgvan4 years ago
4 0
A + b = 15 ..... eq 1
a – b = 12 ...... eq 2

So a = 15 – b
Substitute in eq 2 :

15 – b – b = 12
15 – 2b = 12
–2b = 12 – 15
b = 1.5

So a = 15 – 3/2 = 13.5

4ab = 4 x 13.5 x 1.5 = 81
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General Formulas and Concepts:

<u>Calculus</u>

Differentiation

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  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
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Integration

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<u>Step 1: Define</u>

<em>Identify</em>

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<u>Step 2: Find Arc Length</u>

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Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

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