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erica [24]
3 years ago
13

what is the mass of an object that has a density of 0.7g/cm^3 and a volume of 8cm^3? (The density of an object has the equation

d= m/v)
Mathematics
1 answer:
UNO [17]3 years ago
4 0
Mass=5.6
Find this by plugging your values into the density formula and solving for M.
You might be interested in
Which expression is equivalent to -16 - 7?
alexandr1967 [171]

Answer:

- 16 + ( - 7 )

Step-by-step explanation:

- 16 + ( - 7 ) is same as - 16 - 7.

3 0
3 years ago
In the game of​ roulette, a player can place a ​$4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal
creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}

E(x)=\frac{140-148}{38}

E(x)=\frac{-8}{38}=-$0.2105

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

5 0
3 years ago
Mr. Palmer deposited $850 into a simple interest account for 8 years, earning at an 8% interest rate. What will his total balanc
Andrei [34K]

Answer:

solution given:

principal [P]=$850

time[T]=8years

rate[R]=8%

now

simple interest [S.I.]=\frac{P×T×R}{100} =$ \frac{850×8×8}{100} =$544

so

Total balance=S.I.+P=$544+$850=$1394.

<u>option b.$1,394.00 is your answer</u>

6 0
3 years ago
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 48.0 and 58.
Yanka [14]

Answer: 0.025

Step-by-step explanation:

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].

The probability density function :-

f(x)=\dfrac{1}{58-48}=\dfrac{1}{10}

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-

\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025

Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025

Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025

5 0
3 years ago
Please this is urgent
joja [24]
4 & 9 LCM - 36
8 & 10 LCM - 40
12 & 5 LCM - 60
3 & 6 LCM - 6
3 & 5 LCM - 15
4 & 11 LCM - 44
4 0
2 years ago
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