Answer:
- 16 + ( - 7 )
Step-by-step explanation:
- 16 + ( - 7 ) is same as - 16 - 7.
Answer:
The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.
Step-by-step explanation:
Consider the provided information.
It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.
The probability of winning is 1/38. So, the probability of loss is 37/38.
Now, find the expected value of the game to the player as shown:



Hence, the expected value of the game to the player is -$0.2105.
Now find the expect to loss if played the game 1000 times.
1000×(-$0.2105)=-$210.5
Therefore, the expected loss if played the game 1000 times is -$210.5.
Answer:
solution given:
principal [P]=$850
time[T]=8years
rate[R]=8%
now
simple interest [S.I.]=
=$
=$544
so
Total balance=S.I.+P=$544+$850=$1394.
<u>option b.$1,394.00 is your answer</u>
Answer: 0.025
Step-by-step explanation:
Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].
The probability density function :-

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-
![\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025](https://tex.z-dn.net/?f=%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20%5Cdfrac%7B1%7D%7B10%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%7Cx%7C%5E%7B50.5%7D_%7B50.25%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%5C%20%5B50.5-50.25%5D%3D%5Cdfrac%7B1%7D%7B10%7D%5Ctimes%280.25%29%3D0.025)
Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025
Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025
4 & 9 LCM - 36
8 & 10 LCM - 40
12 & 5 LCM - 60
3 & 6 LCM - 6
3 & 5 LCM - 15
4 & 11 LCM - 44