We can identify that the missing reason in the proof is: Definition of Congruent angles.
<h3>How to give proof of a congruent triangle?</h3>
We know that an angle measure of 90° of ∠ABC in the triangle means that it is a right angle triangle.
We also see that ∠ADB is also a right angle and is equal to 90°.
Now, since they have exactly the same measure, these angles are congruent. Then we can say that the angles are congruent and as such:
∠ABC ≅ ∠ABD
Thus, we can identify that the missing reason is: Definition of Congruent angles.
Read more about Triangle proof at; brainly.com/question/1248322
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Uhm, did you, maybe, type in the problem wrong? The answer to this equation is: 18/5 or 3.6, lol, no worries, though!
Answer:

Step-by-step explanation:
<u>Composite Function</u>
Given f(x) and g(x) real functions, the composite function named fog(x) is defined as:

For practical purposes, it can be found by substituting g into f.
We have:


Computing the composite function:

Operating:

Operating:

Now evaluate for x=4


7/12 - 1 5/12 = 7-5 = 2
= 1 2/12 ( the whole came from 1 5/12 )