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NikAS [45]
3 years ago
13

Which of these statements are true?

Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Because Y and X axis have being shift to the corner of left

You might be interested in
How do you multiply add and divide fractions?
Solnce55 [7]

Answer:

If the denominators are not the same: First, make them the same. Then add or subtract like fractions with the same denominators.

Step-by-step explanation:

the first step when multiplying fractions is to multiply the two numerators. the second step is to multiply the two denominators.  simplify the new fractions. the fractions can also be simplified before multiplying by factoring out common factors in the numerator and denominator.

to add or subtract fractions they must have the same denominator. if the denominators are already the same then it is just a matter of either adding or subtracting the numerators if the denominators are difrent then a common denominator needs to be found.

8 0
3 years ago
What is the greatest common factor of the terms in the polynomial
ruslelena [56]

Answer:

4x^2

Step-by-step explanation:

The greatest common factor is the greatest number that can divide the terms. The greatest number that can divide each term is 4, and the greatest power of x that can divide each term is x^2. This is because it can't be any number greater than 4 since that number would never be able to divide into 4. This is also the reason why x^2 is the greatest power possible. It cannot be greater than anything divisible by itself. Thus, you multiply 4 by x^2 and the answer is 4x^2.

7 0
3 years ago
If y=e5t is a solution to the differential equation
a_sh-v [17]

Answer:

k = 30, y(t) = C_1e^{5t}+C_2e^{6t}

Step-by-step explanation:

Since y=e^{5t} is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}

Then, replacing the derivatives in the equation we have:

25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0

Since e^{5t} is a positive function, we have that

25-55+k = 0 \rightarrow k = 30.

Now, consider a general solution y(t) = Ae^{rt}, A \in \mathbb{R}, then, by calculating the derivatives and replacing them in the equation, we get

Ae^{rt}(r^2-11r+30)=0

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

y(t) = C_1e^{5t}+C_2e^{6t}

8 0
3 years ago
In the diagram of PARALLELOGRAM ABCD, segment BE is perpendicular to segment CED, segment DF is perpendicular to BFC and segment
tiny-mole [99]

Answer:

In parallelogram ABCD

FD is perpendicular to BC

BE is perpendicular to CD

Consider triangle BEC and triangle DFC

FC = EC (Given)

Angle BEC = Angle DFC (=90°)

Angle BCE = Angle DCF (common)

Therefore triangle BEC is congruent to triangle DFC (AAS congruency)

DF = BE (CPCT)

Since the altitudes are equal their bases will also be equal

Therefore BC = DC

Therefore BC = DC = AD = AB

Therefore ABCD is a rhombus

Hope this helps!

Mark me as brainliest

3 0
3 years ago
(x^2 + 5x + 2) – (5x^2 – x – 2) =
zlopas [31]

Answer:

{ \tt{( {x}^{2} + 5x + 2) - (5 {x}^{2} - x - 2)  }} \\  = { \tt{(1 - 5) {x}^{2}  + (5 + 1)x + (2 + 2)}} \\  = { \tt{ - 4 {x}^{2} + 6x + 4 }} \\  = { \tt{ - 2(2 {x}^{2} - 3x - 2) }}

3 0
3 years ago
Read 2 more answers
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