slope = 2 and y-intercept = 0
the equation of a line in ' slope- intercept form ' is
y = mx + c ( mis the slope and c the y-intercept )
given 2x - y = 0 ( add y to both sides )
2x = y or y = 2x + 0 ← in slope-intercept form
with slope m = 2 and y-intercept c = 0
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Since this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis So we have one point Now since the slope is comprised of the "rise" over the "run" this means Also, because the slope is , this means: which shows us that the rise is 3 and the run is 5.
Please mark brainliest! :)
Any polynomial's graph cannot have two simultaneous maxima, so they must contain a minima between them. Thus, the total number of turning points of the graph is 3. Generally, when plotting a polynomial, the number of turning points is:
n = d -1; where d is the degree of the polynomial and n is the number of turning points. Thus, this function's degree must be at least 4. The answer is b.
Answer:
For 1 club it is 120 students
Step-by-step explanation:
360/3=120