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musickatia [10]
3 years ago
9

The Bureau of Labor Statistics1 in the US tells us that, in 2010, the unemployment rate for high school graduates with no colleg

e degree is 9.7% while the unemployment rate for college graduates with a bachelor's degree is only 5.2%. Find the difference in proportions of those unemployed between these two groups and give the correct notation for the difference, with a minus sign. Since the data come from the census, you can assume that the values are from a population rather than a sample. Use the correct notation for population proportions and use subscripts on the proportions to identify the two groups. Assume high school graduates with no college degree are group 1 and college graduates with a bachelor's degree are group 2.
Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Answer:

p_1 -p_2 = 0.097-0.052 = 0.045

So then the difference between the two proportions is 0.045 and if we convert this into % we got

0.045*100= 4.5%

Step-by-step explanation:

For this case we can define the following notation:

p_1 represent the unemployment rate for high school graduates with no college degree

p_2 represent the unemployment rate for college graduates with a bachelor's degree

And for this case we need to find the difference in proportions of those unemployed between these two groups, we want to find:

p_1 -p_2

From the info given we have p_1 = \frac{9.7}{100}=0.097

p_2 = \frac{5.2}{100}=0.052

And the difference:

p_1 -p_2 = 0.097-0.052 = 0.045

So then the difference between the two proportions is 0.045 and if we convert this into % we got

0.045*100= 4.5%

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the correct answer is the third one f(x)=2sin(x)-1

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3 years ago
Part 2:
castortr0y [4]

Answer:

  2. ±1, ±2, ±3, ±4, ±6, ±9, ±12, ±18, ±36

  3. see below for synthetic division

  4. complex roots: ±3i

  5. see the second attachment for a graph (has no symmetry)

Step-by-step explanation:

2. The Rational Root Theorem tells you possible rational roots are the form of ...

  ±(divisor of constant term) / (divisor of leading coefficient)

Here, we're lucky in that the leading coefficient is 1. The constant is 36, and its divisors are 1, 2, 3, 4, 6, 9, 12, 18, 36. Possible rational roots, according to the Rational Root Theorem are ...

  ±1, ±2, ±3, ±4, ±6, ±9, ±12, ±18, ±36

__

3. When actually searching for possible roots, it is useful to narrow down this list of 18 candidates. We can do this using Descarte's Rule of Signs and a couple of other simple tests. The rule of signs has us look at the signs of the coefficients. They are ...

  + + + + +

There are no sign changes, hence <em>no positive real roots</em>. This means we're looking at negative roots only.

We know that p(0) = 36, the constant term. We can evaluate p(-1) simply, by reversing the signs of the odd-degree coefficients and adding them up:

  1 -4 +13 -36 +36 = 10

So p(0) = 36 and p(-1) = 10. The average rate of change is -26, so we expect p(-2) to be zero or less. That value (-2) may be a good first choice for a possible root.

The synthetic division for the root -2 is shown in the first attachment. It shows a remainder of 0, so -2 is a root. The polynomial with the corresponding factor divided out is ...

  q(x) = x^3 +2x^2 +9x +18

__

We can apply the above steps to this polynomial. It will have no positive real roots. The value of q(0) is 18, and the value of q(-1) is -1 +2 -9 +18 = 10. The average rate of change between these points is (18 -10)/(0 -(-1)) = 8, so we expect the function to be zero or negative between x=-2 and x=-3.

Further, we observe that the ratio of the first two coefficients is 1 : 2, the same as the 9 : 18 ratio of the last two coefficients. This suggests we can factor this polynomial by "grouping."

  q(x) = (x^3 +2x^2) +(9x +18) = x^2(x +2) +9(x +2) = (x^2 +9)(x +2)

So, without doing any more synthetic division, we have found a second root at x = -2. This means -2 is a double root.

Our factorization so far is ...

  p(x) = (x +2)^2(x^2 +9)

__

4. The remaining polynomial factor (x^2 +9) has only complex roots:

  x^2 +9 = 0

  x^2 = -9

  x = ±√(-9)

  x = ±3i . . . . the complex roots

__

5. The graph is shown in the second attachment, along with the graph of the final quadratic factor.

The leading coefficient is positive and p(x) is of even degree, so it will have a general U shape, going to +∞ for large positive and negative values of x.

Since x = -2 is a double root, the graph touches the x-axis there, but does not cross it.

The graph of p(x) shows no symmetry.

______

<em>Comment on the graph</em>

With modern graphing calculator software it is entirely feasible to start by graphing the polynomial, then reading the (rational) roots from the graph. The same calculator can effectively divide out those roots. If the result is a quadratic, its vertex form equation can be read from the graph, making it easy to find any additional real or complex roots.

This graph shows ...

  p(x) = (x +2)^2·q(x)

  q(x) = x^2 +9

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