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Volgvan
4 years ago
8

To create an entry​ code, you must first choose 3 letters and​ then, 6 ​single-digit numbers. How many different entry codes can

you​ create?
Mathematics
2 answers:
Anettt [7]4 years ago
7 0
Well, you would use factorization for this, which would be MORE than 54 different codes! :D

cricket20 [7]4 years ago
5 0

Answer:

17576000000

Step-by-step explanation:

26 x 26 x 10 x 10 x 10 x 10 x 10 x 10

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What is the difference between 827 and 533
mezya [45]
294
1
7 /8^27
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395
4 0
4 years ago
PLEASE HELP ! worth 18 points :)
leonid [27]

Answer:

x = 6.6

Step-by-step explanation:

law of cosines:

x² = b² + c² - 2ac · cosX

x² = 5² + 8² - 2(5 · 8) · cos 55°

x² = 25 + 64 - 80· cos 55°

x² = 25 + 64 - 45.89

x² = 89 - 45.89

x² = 43.11

x = √43.11

x ≈ 6.6

3 0
3 years ago
4: Find the equation of the line perpendicular to y = ¼ x + 2, passing through the point (-3,0).
skelet666 [1.2K]

Your answer is C. Y= -4x-12

4 0
4 years ago
Im not sure if this is correct. I need help!​
Rus_ich [418]

Answer:

Option 3

Step-by-step explanation:

If (x, y) is on h(x), then (y, x) is on the inverse.

Thus, if (4, 2) is on the inverse, then (2, 4) must be on the original. (Which it is not, so this option is incorrect)

If (0, 1/2) is on the inverse, then (1/2, 0) must be on the original. (It is not, so this option is also incorrect)

If (0, 1) is on the inverse, then (1, 0) must be on the original. (It is not, so this option is also incorrect)

If (-5, 1) is on the inverse, then (1, -5) must be on the original. (It is not, so this option is incorrect)

The correct answer would be the third option.

5 0
3 years ago
Which statement BEST describes the growth of bacteria modeled by the function f(x)=1.8x
lara [203]

Answer:


Step-by-step explanation:

f(x) = 1.8x is a linear function and does not model the growth of bacteria.  Perhaps you meant f(x) = 1.8^x, which is an exponential function whose initial value is 1.  Please ensure that you have copied down this problem exactly as it was presented.



6 0
3 years ago
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