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3 years ago

The area of a triangle is 1/2(base)(height) or base times height divided by two.

Mathematics

1 answer:

blagie [28]3 years ago

7 0

Answer:

both

Step-by-step explanation:

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The volume of an oblique pyramid with a square base is V units3 and the height is h units.Which expression represents the area o

melamori03 [73]

Answer: a) $\dfrac{3V}{h}\ units^2$

Step-by-step explanation:

We know that the volume of an oblique pyramid is given by :-

$\text{Volume}=\dfrac{1}{3}\text{(Base Area x height) }$

If the volume of an oblique pyramid with a square base is V units³ and the height is h units.

Then, we have

$V=\dfrac{1}{3}\text{(Base Area x h) }$

Multiply 3 on both sides , we get

$3V=\text{(Base Area x h) }$

Divide both sides by h , we get

$\dfrac{3V}{h}=\text{Base Area }$

i.e. $\text{Base Area }=\dfrac{3V}{h}\ units^2$

Hence, the expression represents the area of the base of the pyramid = $\dfrac{3V}{h}\ units^2$

Hence, the correct answer is a) 3 v/h units^2

7 0

3 years ago

Read 2 more answers

Given: f(n) = 3n-5 and g(n) = 2n-1<br>Find: (fog)(5

laiz [17]

Answer:

Step-by-step explanation:

So we have the two functions:

$f(n)=3n-5\text{ and } g(n)=2n-1$

And we want to find (fog)(5). This is the same as:

$(f\circ g)(5)=f(g(5))$

So, find g(5) first:

$g(5)=2(5)-1\\$

Multiply and subtract:

$g(5)=10-1=9$

So, we can substitute:

$f(g(5))=f(9)$

Find the value:

$f(9)=3(9)-5$

Multiply and subtract:

$f(9)=27-5=22$

So:

$(f\circ g)(5)=22$

And we're done!

4 0

3 years ago

The long side of a rectangle is 3x+21 units, and it's area is 3x^2+33x+84. Find the width

ella [17]

L*w=area
(3x+21)*w=3x^2+33x+84
w=(3x^2+33x+84)/3x+21
(3(x+4)(x+7))/3(x+7)
w=x+4

3 0

3 years ago

SQ is an angle bisector find x and the perimeter of the triangle PRQ 32,40,2x+3, 3x-1

Ket [755]

Yes he and his family have a good day tomorrow and I will let you the mason jar of the money he is going we I am so sorry I just need points for the questions

8 0

2 years ago

Find the inverse, g−1(x), of the following function: g(x) = 4x - 11

Sphinxa [80]

Answer:

$g^{-1}$ (x) = $\frac{x+11}{4}$

Step-by-step explanation:

let y = g(x) and rearrange making x the subject, that is

y = 4x - 11 ( add 11 to both sides )

y + 11 = 4x ( divide both sides by 4 )

$\frac{y+11}{4}$ = x

Change y back into terms of x , with x = $g^{-1}$ (x) , thus

$g^{-1}$ (x) = $\frac{x+11}{4}$

7 0

3 years ago

The area of a triangle is 1/2*(base)*(height) or base times height divided by two.

The area of a triangle is 1/2(base)(height) or base times height divided by two.