Multiply 2 by 1/2 to get 1.
Multiply 1 by 2/3 to get 2/3.
Multiply 2/3 by 3/4 to get 6/12 = 1/2.
Multiply 1/2 by 4/5 to get 4/10 = 2/5.
Multiply 2/5 by 5/6 to get 10/30 = 1/3.
Multiply 1/3 by 6/7 to get 6/21 = 2/7. (I suspect there's a typo in the question.)
And so on, so that the <em>n</em>th term in the sequence is multiplied by <em>n</em>/(<em>n</em> + 1) to get the (<em>n</em> + 1)th term.
Recursively, the sequence is given by
We can solve this exactly by iterating:
and so on down to
or
and with lots of cancellation, we end up with
Answer:
I think its B. ?????
Step-by-step explanation:
Answer:
√16×81 = 4×9 or √1296 = 36
√16×√81 = 4×9 = 36
Step-by-step explanation:
√81×16
We simplify 81 and 16 by prime factorisation (expressing a number as a product of its prime factors).
√81 = √3×3×3×3 = √9×9 = √9² = 9
√16 = √2×2×2×2 = √4×4 = √4² = 4
Answer:
B. (2a +3b)(4a -c)
Step-by-step explanation:
Group the terms pairwise, then factor each pair.
... (8a² -2ac) +(12ab -3bc)
2a is a common factor in the first pair of terms; 3b is a common factor in the second pair of terms. We can factor those out.
... = 2a(4a -c) +3b(4a -c)
Then we see that (4a-c) is a common factor in the result. We can factor that out.
... = (2a +3b)(4a -c) . . . . matches selection B
Answer:
Step-by-step explanation:
By the trapezoid midsegment theorem,
2x = (x-6) + (2x-8)
2x = x - 6 + 2x - 8
2x = 3x - 14
x = 14
So we know AD = 8, EF = 14, and BC = 20
