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stepan [7]
3 years ago
15

In a group of 36 children, there are twice as many boys as girls, how many girls are there?

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
12
For every 1girl there are 2boys

1girl+2boys= 3/1girl
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Help geometry is very hard lol
blsea [12.9K]

Answer:

A. is your answer.

Step-by-step explanation:

If you look at the picture, you can see that S and T are congruent with each other.

LG and TD are not congruent along with L and D.

A. is your answer.

3 0
3 years ago
Which graph is defined by the function given below?
jeka57 [31]
Graph A since it crosses all 4 regions of the graph
7 0
3 years ago
Find the GCF of the monomials: 32x^2 and 24x^2y
aev [14]

Answer:

8x^2

Explanation:

First, do prime factorization of each of the coefficients:

32   ⇒   2^5

24   ⇒   2^3, 3

The greatest common factor (GCF) of the coefficients is 2^3 = 8.

Next, find the GCF of the variables:

x^2

x^2, y

The GCF of the variables is x^2.

Finally, multiply the GCF of the coefficients by the GCF of the variables to get:

8x^2

4 0
2 years ago
What two numbers have a product of -25 and a sum of 24?​
NemiM [27]
-1 and 25

have a good day!
7 0
3 years ago
What is √-11 in the form a+bi?
Mice21 [21]

Given:

The number is \sqrt{-11}.

To find:

The a+bi form of given number.

Solution:

We have,

\sqrt{-11}

It can be written as

\sqrt{-11}=\sqrt{-1\times 11}

\sqrt{-11}=\sqrt{-1}\times \sqrt{11}      [\because \sqrt{ab}=\sqrt{a}\sqrt{b}]

\sqrt{-11}=i\times \sqrt{11}      [\because \sqrt{-1}=i]

\sqrt{-11}=\sqrt{11}i

Here, real part is missing. So, it can be taken as 0.

\sqrt{-11}=0+\sqrt{11}i

So, a = 0 and b=\sqrt{11}.

Therefore, the a+bi form of given number is 0+\sqrt{11}i.

5 0
3 years ago
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