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Ivan
3 years ago
10

tickets at a particular movie theatre have different rates for adults and children. on a friday the theatre sold 4 adult tickets

and 7 child tickets for $83. the next day, the theatre sold 5 adult tickets and 6 children tickets for $90. what are the prices for the adult ticket and the price for the child tickets. Use substitution method
Mathematics
1 answer:
maria [59]3 years ago
4 0
Using elimination method. Using substitution will cause some fraction problems.

c- child tickets
a- adult tickets

4a + 7c = $83
5a + 6c = $90

multiply by -5

-20a - 35c = -$415
20a + 24c = $360

-11c= -$55
c = $5 child tickets

4a + 7(5)= $83

4a + 35 = $83

4a = $48

a= $12 adult tickets

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The answer to the question is,

12 sin(∠B) = 2,           12 sin(∠C) = √3+√35

Sin rule is,

sin(A)/BC = sin(B)/AC = sin(C)/AB

sin(B) = (sin(A)×AC)/BC

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To solve this question we apply sin rule,

Now we take

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12 sin(∠B) =12 ((1/2)×(1/3))

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now we find the value of 12 sin(∠C)

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now put the value of 12 sin(∠B) = 2

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12 sin(∠C) = 2×[cos(π/6)+(BC/AC)×(cos B)]

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12 sin(∠C) = 2×[(√3/2)+3×(cos B)]

cos B= √1-sin²B

12 sin(∠C) = 2×[(√3/2)+3×√(1-sin²B)]

12 sin(∠B) = 2

sin B = 1/6

12 sin(∠C) = 2×[(√3/2)+3×√(1-(1/6)²]

12 sin(∠C) = 2×[(√3/2)+3×√1-(1/36)]

12 sin(∠C) = 2×[(√3/2)+3×√(36-1)/36]

12 sin(∠C) = 2×[(√3/2)+3×√(35/36)]

12 sin(∠C) = 2×[(√3/2)+(3/6)×√35]

12 sin(∠C) = 2×[(√3/2)+(1/2)×√35]

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Hence the answer is,

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