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Ierofanga [76]
4 years ago
5

Please someone help ASAP

Mathematics
1 answer:
tatyana61 [14]4 years ago
5 0
You still need help...???

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Find the absolute value of the difference between each data value and the mean: data value – mean

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How can you find odd numbers that u can put as a fraction
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Fractions are not even numbers or odd numbers, because they are not whole numbers. They are only parts of numbers, and can be written in different ways.

Step-by-step explanation:

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-4x - 10x<br> Combine Like Terms
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-14x

Step-by-step explanation:

-4x+-10x =-14x

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Write the following number in standard form: 3.471 × 10^−5
muminat
0.00003471 is the correct answer I believe
4 0
3 years ago
Of the students attending a school party, 60% of the students are girls, and 40% of the students like to dance. After these stud
elena-s [515]

Answer:

252 students at the party like to dance

Step-by-step explanation:

Given:

60% of the students are girls

40% of the students like to dance

20 more boy students

Percentage of the girls in the party = 58%

To Find:

How many students now at the party like to dance=?

Solution:

Let the number of girls be g.

Let the number of total people originally be t.

We know that

\frac{g}{t}=\frac{60}{100}

\frac{g}{t}=\frac{3}{5}----------------------------------(1)

We also know that

\frac{g}{t+20}=\frac{58}{100}

\frac{g}{t+20}=\frac{29}{50}-----------------------------(2)

We now have a system of equation from (1) and (2)

3t=5g

g = \frac{3t}{5} ------------------------(3)

50g=29t+580------------------------(4)

Substituting 3 in 4, we get

50(\frac{3t}{5})=29t+580

(\frac{150t}{5})=29t+580

30t =29t+580

30t -29t = 580

t =589

So originally there was 580 students

In this 580 students 40% liked to dance

Then the number of students liked to dance =

=> 40\% \text{of} 580

=>\frac{40}{100} \times 580

=>0.4 \times 580

=> 232

We also know that with these people, 20 boys joined, all of whom like to dance.

Now the number of students like to dance  = 232+20 = 252 students

7 0
3 years ago
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